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Novay_Z [31]
3 years ago
11

How do I use elimination for he equations 2x+10y=-20 and -x+4y=28?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
3 0

Answer:

Using the elimination method to solve for x and y; ANSWER: y=2 & x=-20

Step-by-step explanation:

1) It helps to visualize the equation if you put the second equation underneath the first like regular adding.  

  (2x+10y= -20)

+ (-x+4y= 28)

____________

          ?

2) You always want to cancel out one value (x or y) to start the process.

In this case, if I can get a -2x to cancel out 2x (neg. and positive cancel), that would cancel out the x's in the two equation. To do that, I would multiply by 2 to the second equation and add like you would normally (like terms with like terms, x with x and y with y)

2x+10=-20   2(-x+4y=28) ---> 2x+10y= -20 <u><em>plus</em></u> -2x+8y=56 --->18y=36 (this is the final simplified outcome)

3) find y so y =36/18     so y =2

4) Plug y=2 back into one of the original equation and solve for x

2x+10(2)= -20 ---> x=-20

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There are 158 students registered for American History classes. There are twice as many students registered in second period as
Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<h3>x = 28</h3>

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<h3>y = 56</h3>

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

<h3>z = 74</h3>

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

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2 years ago
Solve for x in the equation 3 x squared minus 18 x + 5 = 47.
svetlana [45]

Answer:

(4+√142)/(3) or x=(4-√142) /3

Step-by-step explanation:

(4+√142)/(3) or x=4-√142 /3

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Step-by-step explanation:

Start with What’s inside the parentheses

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The divide.

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Read 2 more answers
-2(3x-3)=4x please help solve for x=
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Answer:

exact form:

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Decimal form:

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