Answer:
3.38 moles.
Explanation:
The following data were obtained from the question:
Mass of copper (Cu) = 215 g
Number of mole of copper (Cu) =...?
The number of mole of copper (Cu) in 215 g can be obtained as follow:
Mass of copper (Cu) = 215 g
Molar mass of copper (Cu) = 63.55 g/mol
Number of mole of copper (Cu) =...?
Mole = mass /Molar mass
Mole of Cu = 215/63.55
Mole of Cu = 3.38 moles
Therefore, 3.38 moles of copper (Cu) is present in the sample.
Answer:
No
Explanation:
Let us examine this problem carefully:
Given compound is N₂O
Molecular mass = 88g
Now,
The empirical formula is the simplest formula of a compound.
The molecular formula is the true formula of the compound that shows that actual ratios of the atoms in a compound.
To find if they both have the same molecular and empirical formula, they must have the same molecular mass.
For N₂O;
Molecular mass = 2(14) + 16 = 44g/mole
But the true and given molecular formula of the compound is 88g/mole
This shows that the compound given is the empirical formula of the compound.
Molecular formula:
molecular mass of empirical formula x n = molecular mass of molecular formula
n =
= 2
Molecular formula of compound = 2(N₂O) = N₄O₂
Therefore the empirical and molecular formulas are not the same
Answer:
57.05
Explanation: the formula is...
length x width x height
Answer:
It does not matter where the sample of water came from or how it was prepared. Its composition, like that of every other compound, is fixed.
M = n / V
Where, M is molarity (M or mol/L), n is number of moles of the solute (mol) and V is volume of the solution (L).
Here the solute is KNO₃.
The given molarity is 1.3 M
This means 1L of solution has 1.3 moles of KNO₃.
Hence moles in 600 mL = 1.3 M x 0.6 L = 0.78 mol
Therefore to make 1.3 M KNO₃ solution, needed moles of KNO₃ is 0.78 mol