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skelet666 [1.2K]
4 years ago
11

A topographic map with points A and B labeled. Point A is on a contour line with number 800. Point B is on a contour line with n

umber 700.
Use the drop-down menus to answer the questions about the topographic map.

What is the elevation at point A?

What is the elevation at point B?

What is the relief between points A and B?

Chemistry
2 answers:
RideAnS [48]4 years ago
4 0

Answer:

800 700 and 100 :)

Explanation:

KonstantinChe [14]4 years ago
4 0

Answer:

800 feet, 700 feet and 100 feet

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A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL
ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

6 0
3 years ago
A solution has [H+] = 2.35 × 10-3 M. Find the [OH-] for this solution
Aleks04 [339]

Answer:

[OH-] for this solution is 4.255*10^-12

Explanation:

We are given

[H+] = 2.35 × 10-3 M

we need to find the concentration of [OH-]

we know from Equilibrium

[H+][OH-] = 10^-14

[OH-] = 10^14/2.35*10^10^-3

[OH-] = 0.4255*10^-11

[OH] = 4.255*10^-12

Therefore the Concentration  of [OH-] for this solution is 4.255*10^-12

3 0
4 years ago
Reduce the following equation to a net ionic equation: 2Na+ + SO4^2- + Ba^2+ + 2Cl^- ---> 2Na^+ + 2Cl^- + BaSOv4
Eduardwww [97]

net ionic equation

B) SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)

Explanation:

We have the following chemical equation:

2 Na⁺ (aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2 Cl⁻ (aq) → 2 Na⁺ (aq) +  2 Cl⁻ (aq) + BaSO₄ (s)

To get the net ionic equation we remove the spectator ions and we get:

SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)

were:

(aq) - aqueous

(s) - solid

Learn more about:

net ionic equation

brainly.com/question/2094377

brainly.com/question/9489859

#learnwithBrainly

8 0
4 years ago
Read 2 more answers
Sample of 76 G of NaCl is dissolved to make 1 L of a solution what is the molarity of the solution
natima [27]
Molarity =  Moles/Liter

Use the molecular atomic mass of NaCl to convert from grams to moles.
Molecular mass of NaCl is the sum of its atomic masses. Look at the periodic table to find these. Na is 23 g/mol and Cl is 35.5 g/mol ,
so NaCl = 23 + 35.5 = 58.5 g/mol

multiply to cancel out grams
76 g NaCl * (1mol / 58.5 g NaCl) = 1.3 mol NaCl

over 1 Liter is just 1.3 M NaCl



6 0
3 years ago
Read 2 more answers
The temperature of a gas is 100 K and its volume is 500.0 ml. If the volume increases to 1,000.0 ml,
olga55 [171]
1000000000000000 that’s the answer
5 0
3 years ago
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