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BaLLatris [955]
3 years ago
7

I need help with this.

Mathematics
1 answer:
likoan [24]3 years ago
5 0

a quick clarification and then some.

Profit is what's leftover after the cost is subtracted from the revenue, or namely, if you sell a product for some amount, say 10, and you sold 100 of those, so you made 10*100 or 1000, that's the revenue or the income coming in, however, in making the product you had to cover some expenses, like if it's clothing, well, you have to buy the garment and saw it, have premises and machines to make the clothing and so on, all that's expenses, and since it's out of pocket money, is Cost, if you subtract that Cost from the 1000 in Revenue, what's leftover, that surplus is Profit.

this company sells "p" units, each at $855, so their Revenue will just be 855p, expenses or Cost is a fixed amount of $6780, so the profit comes from their difference.

on a given month, they sold 250, namely p = 250, so their Revenue is just 250*855 = 213750 bucks, however, we need to remove the Costs of 6780, 213750 - 6780 = 206970, that's our Profit.

now, the CEO takes a bite of 15% of that

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{15\% of 206970}}{\left( \cfrac{15}{100} \right)206970}\implies 31045.5

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An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th
monitta

Answer:

a) n =1623

b) ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208    

Step-by-step explanation:

1) Notation and definitions

n random sample taken

\hat p=0.19 estimated proportion of customers are not satisfied with the service provided by the local dealer

Confidence =0.96 or 96%

Me= 0.02 represent the margin of error

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by \alpha=1-0.96=0.04 and \alpha/2 =0.02. And the critical value would be given by:

z_{\alpha/2}=-2.0538, z_{1-\alpha/2}=2.0538

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.19(1-0.19)}{(\frac{0.02}{2.0538})^2}=1622.912  

And rounded up we have that n=1623

Part b

The margin of error is given by:

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    

So then if w replace the value of n obtained from part a we got:

ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208    

3 0
3 years ago
(7x-y=7<br>(x+2y=6 estimate the solution to the system of equations ​
jolli1 [7]

Multiply the first equation by 2 to then use elimination by adding the 2 equations.

So, 14x-2y=14

+. x+2y=6

Equals 15x=20 so x=20/15=4/3

Plug in to first equation to get y

7(4/3)-y=7

28/3-y=7

28/3-y=21/3

So y=7/3

Plug both x and y into second equation to check

4/3+2(7/3)=

4/3+14/3=18/3=6 it works

So x=4/3, y=7/3

Hope this helps! Have a blessed day!

8 0
4 years ago
What is the product?
viva [34]

Answer:

its C

Step-by-step explanation:

I hope this helps :)

3 0
3 years ago
20x3 - 45x2 + 21x + 25 \<br><br> 4x - 5
tiny-mole [99]

Answer:

80x3 - 180x2 + 109x - 20

—————————————

               4            

Step-by-step explanation:

4 0
3 years ago
A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w
Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds.  Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

t = 5.0625

Step-by-step explanation:

Given

h(t)=-16t^2+80t+5

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

0=-16t^2+80t+5

Reorder

-16t^2+80t+5 = 0

Using quadratic formula, we have:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = -16      b =80      c = 5

So, we have:

t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}

t = \frac{-80\±\sqrt{6400 +320}}{-32}

t = \frac{-80\±\sqrt{6720}}{-32}

t = \frac{-80\±82.0}{-32}

This gives:

t = \frac{-80+82.0}{-32} or t = \frac{-80-82.0}{-32}

t = \frac{2}{-32} or t = \frac{-162}{-32}

t = -\frac{2}{32} or t = \frac{162}{32}

But time can not be negative.

So, we have:

t = \frac{162}{32}

t = 5.0625

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0
3 years ago
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