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belka [17]
3 years ago
9

Write an equation in slope-intercept form of the line passing through (0, 3) and (2, -1).

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

sim eu também preciso desta respota

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Let g be the function given by g(x)=x^2*e^(kx) , where k is a constant. For what value of k does g have a critical point at x=2/
ArbitrLikvidat [17]
G `( x ) =2x * e^{kx}  + k x^{2} *e^{kx} = \\  = xe^{kx}(2 + kx )
2 + k x = 0
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Help pls <br> Find the value of x
elena55 [62]

Answer:

x=61

Step-by-step explanation:

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2 years ago
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alisha [4.7K]

Answer:

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Step-by-step explanation:

Given:

Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).

So, the 'x' value is 3 and 'y' value id -4.

Using Pythagoras Theorem, we find the hypotenuse.

Hypotenuse = \sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

Now, using the sine ratio for the angle, we have

\sin \theta=\frac{Opposite}{Hypotenuse}\\\sin \theta=\frac{-4}{5}\\\sin \theta=-\frac{4}{5}

Therefore, the value of \sin \theta is -\frac{4}{5}.

The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,

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luda_lava [24]
2350+ 2350*.03 = <span>2420.5</span>
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