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goldenfox [79]
3 years ago
5

Write an expression that is equivalent to 4(b+2)-3b

Mathematics
2 answers:
vekshin13 years ago
6 0
Ok so first we need to distribute so:
<span>=<span><span><span><span><span>(4)</span><span>(b)</span></span>+<span><span>(4)</span><span>(2)</span></span></span>+</span>−<span>3b
</span></span></span>=<span>4b+8+−3b
</span>So now that we've distrubuted that we are now going to Combine Like Terms:
<span>=<span><span><span>4b</span>+8</span>+<span>−<span>3b
</span></span></span></span><span>=<span><span>(<span><span>4b</span>+<span>−<span>3b</span></span></span>)</span>+<span>(8)
Finally your answer is:
</span></span></span><span>=<span>b+<span>8
I hope this helps you!</span></span></span>
xz_007 [3.2K]3 years ago
6 0
4 (b + 2 ) - 3b

....

Distribute 4 into the parenthesis.

......

We now have: 4b + 8 - 3b.

............

Time to combine like terms.

...................

Which gives us ---> 1b + 8
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What is the value of x? (Please help ASAP)
Rudiy27

Answer:

110

Step-by-step explanation:

Bigger then 90 less than 120

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Janet makes homemade dolls. Currently, she produces 23 dolls per month. If she increased her production by 18%, how many dolls w
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4 0
3 years ago
Y= 1/2x+ 2 to make the x the subject.
timofeeve [1]

Answer:

x=2y-4

Step-by-step explanation:

y=\frac{1}{2} x+2

"To make x the subject" means to have the equation with all the terms in x on one side. As of now, y is the subject of the equation.

You start by subtracting 2 from both sides, you should get the following.

y-2=\frac{1}{2} x

Then you multiply by 2 from both sides, you should end up with the following.

2(y-2)=x

Therefore, you get the following.

x=2(y-2)

Finally, you distribute and get the answer.

x=2y-4

5 0
2 years ago
There are 300 students. for every 8 are boys, and for every seven are girls. how many boys?
katen-ka-za [31]
8+7=15
300/15=20
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140 + 160 = 300

Hope this helps!

4 0
3 years ago
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
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