The two processes that remove carbon dioxide from the atmosphere are photosynthesis and absorption. Respiration and volcanism, or the eruption of molten rock, are the two processes that provide carbon to the atmosphere.
carbon is removed from the atmosphere through photosynthesis and replaced with O2. O2 is removed from the atmosphere during respiration and replaced with carbon . These processes, however, are not in equilibrium. Not every organic substance oxidizes. Photosynthesis and metabolism are the two fundamental processes that take place during the natural carbon cycle. Plants consume carbon dioxide during photosynthesis to create oxygen, and they also make carbon dioxide during metabolism.
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B) cold to hot hope this helps
Cytotoxic T cells are rapid killers of infected target cells. Within minutes of the interaction of a cytotoxic T cell with a target cell, the program of apoptosis in the target cell is initiated. This rapid activity is a consequence of The extremely rapid production of granzymes and perforin by cytotoxic effector cells upon encountering a target cell.
- A type of T cell known as a cytotoxic T cell (CD8+ T cell) is in charge of removing things that the immune system recognizes as dangerous.
- Cytotoxic T cells are essential for controlling bacterial growth and illnesses in the body.
- By instructing their targets to undergo apoptosis, cytotoxic T lymphocytes kill their prey.
- Cytotoxic T cells can instruct antigen-specific target cells to die within 5 minutes of coming into contact with them when they are mixed with target cells and quickly brought into contact by centrifugation.
- The speed with which cytotoxic T cells can induce apoptosis in their targets is due to the release of prepared effector molecules that trigger the target cell's own endogenous apoptotic pathway.
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Xylem transports water and minerals from the roots to the leaves of the plant, where it is used in the production of food.
Answer:
362 nucleosomes
Explanation:
A nucleosome repeat is made up of the DNA (146 bp) wrapped around the core nucleosome particle and the linker DNA (110 bp as in this situation). We can conclude that, every repeat stands for 256 (146 + 110) base pairs of DNA.
We are given the length of the entire region to be 92,672 bp long,
To determine the number of nucleosomes to organize the region into the 10nm fiber structure
Let,
Number of nucleosomes =
the length of the entire region
------------------- -----
base pairs of DNA.
= 92,672
-------
256
= 362 nucleosomes
Therefore, 362 nucleosomes is needed to structure the region into the 10nm fiber structure.
