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lord [1]
3 years ago
7

You have 10 different styles of toilet paper stored in your house you plan to take out 3 types for each of the bathrooms in your

house how many ways can you arrange them
Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

The correct answer is 720.

Step-by-step explanation:

There are 10 different styles of toilet paper available in the house.

We need to choose 3 types from these 10 styles.

Therefore number of ways we can select these 3 types are given by \left[\begin{array}{ccc}10\\3\end{array}\right] ways = 120 possible ways.

Now we need to put these toilet paper in each of the 3 bathrooms. So we have possible 3! = 6 possible ways.

Therefore the number of ways one would select 3 toilet paper and then placing each of the bathrooms in the house is given by 120 × 6 possible ways = 720 ways.

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Rufina [12.5K]
2(x+9)=7
If you wanted to simplify;
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x=-11/2 (Division Property of Equality)
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If berry has 30 ounces of coke and sells each ounce for 8 bucks an ounce how many ounces do you get if you spend 13 dollars on c
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Combine the like terms to create an equivalent expression 5z + 3 -3z
Valentin [98]

Answer:

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Step-by-step explanation:

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7 0
4 years ago
Read 2 more answers
-3x + 4y = 95 <br> x + 5y = 38
NARA [144]
We can solve this by elimination, in order to do this we need to multiply the bottom equation by three to cross out the X

(x+5y=38)3 3x+15y=114

-3x+4y=95
3x+15y=114

then add the two equations together and the X will cancel out

19y=209
-----  -----
19     19

y=11

then plug that in into one of the equations

x+55=38
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4 years ago
Never was given anything to help solve they just assume you know it
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Answer: 0.4575

Step-by-step explanation:

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