The total number of tries = 10
The tries are { <span>110 111 100 000 101 111 100 000 011 010 }
</span><span />
Where: 0 representing heads and 1 representing tails
The tries which are heads came up more than once in 3 coin flips { 100 000 100 000 010 }
The number of the tries which are heads came up more than once in 3 coin flips = 5
∴ The probability of heads coming up more than once in 3 coin flips = 5/10 = 1/2
Add: 5 + 3 = 8
Exponentiation: the result of step No. 1 ^ 2 = 8 ^ 2 = 64
Add: 32 + 2 = 34
Subtract: the result of step No. 2 - the result of step No. 3 = 64 - 34 = 30
Multiple: 5 * the result of step No. 4 = 5 * 30 = 150
Add: 8 + the result of step No. 5 = 8 + 150 = 158
plz mark me as brainliest :)
I believe it’s 3 to the 34 power
Answer:
Step-by-step explanation:
This is a differential equation problem most easily solved with an exponential decay equation of the form
. We know that the initial amount of salt in the tank is 28 pounds, so
C = 28. Now we just need to find k.
The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is
. Thus, the change in the concentration of salt is found in
inflow of salt - outflow of salt
Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

Therefore,
or just
and in terms of time,

Thus, our equation is
and filling in 16 for the number of minutes in t:
y = 24.834 pounds of salt
Wish I can help , but you didn’t show any fractions nor anything I can use to answer your question . Can you mark me brainliest for effort !?