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Anastasy [175]
3 years ago
12

Find x, round to the nearest tenth.

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

Step-by-step explanation:

Law of Cosines

x = √(40²+12² - 2·40·12·cos(37°)) ≅ 31.3 units

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Jason would like to estimate the probability of heads coming up more than once in 3 coin flips. To do this, he has a computer ra
Umnica [9.8K]
The total number of tries = 10

The tries are  { <span>110 111 100 000 101 111 100 000 011 010  }
</span><span />
Where: 0 representing heads and 1 representing tails

The tries which are heads came up more than once in 3 coin flips { 100 000 100 000 010  }

The number of the tries which are heads came up more than once in 3 coin flips = 5

∴ The probability of heads coming up more than once in 3 coin flips = 5/10 = 1/2

5 0
3 years ago
8 + 5[(5 + 3)2 - (32 + 2)]
jeka57 [31]

Add: 5 + 3 = 8

Exponentiation: the result of step No. 1 ^ 2 = 8 ^ 2 = 64

Add: 32 + 2 = 34

Subtract: the result of step No. 2 - the result of step No. 3 = 64 - 34 = 30

Multiple: 5 * the result of step No. 4 = 5 * 30 = 150

Add: 8 + the result of step No. 5 = 8 + 150 = 158

plz mark me as brainliest :)

3 0
3 years ago
Read 2 more answers
Consider the power 34.
Vikentia [17]
I believe it’s 3 to the 34 power
4 0
3 years ago
Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

3(\frac{y}{400})

Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
3 years ago
Which of the following is equal to the fraction below?
Alecsey [184]
Wish I can help , but you didn’t show any fractions nor anything I can use to answer your question . Can you mark me brainliest for effort !?
4 0
3 years ago
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