A right triangle △ABC with right angle C is inscribed in a circle. Find the radius of this circle if: Given m∠C = 90°, k(O, r) i
nscribed in △ABC, AC = 8 cm, BC = 6 cm. Find r.
2 answers:
Answer:
5
Step-by-step explanation:
Answer:
The radius is 
Step-by-step explanation:
we know that
The inscribed angle is half that of the arc it comprises.
so


substitute
![90\°=(1/2)[arc\ AB]](https://tex.z-dn.net/?f=90%5C%C2%B0%3D%281%2F2%29%5Barc%5C%20AB%5D)

That means----> The length side AB of the inscribed triangle is a diameter of the circle
Applying Pythagoras Theorem
Calculate the length side AB



-----> is the diameter
Find the radius
-----> the radius is half the diameter
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Answer:
Step-by-step explanation:
It’s a repeating pattern.
i² = -1
i³ =(i²)i = (-1)i = -i
i⁴ = i³i = -i² = 1
i⁵ = (i⁴)i = (1)i = i
i⁶ = i⁵i = i² = -1
...
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Answer:
Adjacent length = √(50) m
Pythagorean theorem:
a^2 + b^2 = c^2
a = √(50) m
b = √(50) m
c^2 = √(50)^2 + √(50)^2
c^2 = 50 + 50
c^2 = 100
c = 10 m
Diagonal = 10 m
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