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bogdanovich [222]
3 years ago
14

A right triangle △ABC with right angle C is inscribed in a circle. Find the radius of this circle if: Given m∠C = 90°, k(O, r) i

nscribed in △ABC, AC = 8 cm, BC = 6 cm. Find r.
Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
7 0

Answer:

5

Step-by-step explanation:

Anastaziya [24]3 years ago
6 0

Answer:

The radius is r=5\ cm

Step-by-step explanation:

we know that

The inscribed angle is half that of the arc it comprises.

so

m

m

substitute

90\°=(1/2)[arc\ AB]

arc\ AB=180\°

That means----> The length side AB of the inscribed triangle is a diameter of the circle

Applying Pythagoras Theorem

Calculate the length side AB

AB^{2}=AC^{2}+BC^{2}

AB^{2}=8^{2}+6^{2}

AB^{2}=100

AB=10\ cm -----> is the diameter

Find the radius

r=10/2=5\ cm -----> the radius is half the diameter

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All the edges of a regular square pyramid have length 8. find the Volume of the pyramid, Lateral area of the pyramid and the Tot
RUDIKE [14]

Answer:

V = 120.6796

LA = 110.8513

SA = 174.8513

Step-by-step explanation:

Let me know if you need more of an explanation for any of these

First we need the height, one way to find that out is to use the diagonal of the  and one of the diagonal edges of the pyramid.  Specifically we will need half of the diagonal of the square.  We will call the diagonal of the square d.

8^2+8^2=d^2\\d=\sqrt{64+64} \\d=\sqrt{128}

Gonna leave it like that for ease of writing.  So then half of the diagonal is \frac{\sqrt{128}}{2}

The height, h, will be (\frac{d}{2})^2+h^2 = 8^2.  Plugging everything in gets us h=\sqrt{32}

last, we need to find slant height, which we will call s.

(\frac{8}{2})^2+h^2 = s^2\\s=\sqrt{48}

s is also the height of the triangles for purposes of finding area.  Now for the volume and areas.

Volume is area of the base times height divided by 3, so V=8^2\frac{\sqrt{32} }{3}  = \frac{64\sqrt{48} }{3} = 120.6796

Lateral area is the sum of the four areas of the triangles, and each of those are \frac{8*h}{2} so the whole lateral area is 4 times that.  So we get 4\frac{8\sqrt{32} }{2} =110.8513

Total surface area is the lateral surface area + the area of the base, so 110.8513 + 64 = 174.8513

6 0
3 years ago
163, 159, 155, 151.... What will the 23rd term in this sequence be?
Bogdan [553]
The rule is n-4;
163 - 4 = 159
159 - 4 = 155
155 - 4 = 151
151 - 4 = 147

A quick way to solve this is to mutliply 4 by 23 and subtract the product from the 1st term.

23 x 4 = 92
163 - 92 = 71

The 23rd term is 71.

I hope this helps!
3 0
3 years ago
Read 2 more answers
I WILL MARK BRAINLIEST IF CORRECT!
lora16 [44]
The answer is D, x=3
3 0
3 years ago
Read 2 more answers
Please help me on this quick the work is due today
tester [92]

Answer:

1. 52 degrees 2. D

Step-by-step explanation:

1. The interior angles of a triangle add up to 180, so you can do 180 - 36 - 92 to find the third angle.

180 - 36 - 92 = 52 degrees

2. the angle XYZ has to equal the sum of the angles WXY and XWY. This means that 115 = 45 + XWY

115 - 45 = 72

XWY = D. 70 degrees

4 0
3 years ago
Show all work to identify the asymptotes and state the end behavior of the function f(x)=5x/x-25
Nina [5.8K]

Using the asymptote concept, it is found that:

  • The vertical asymptote is of x = 25.
  • The horizontal asymptote is of y = 5.
  • Considering the horizontal asymptote, it is found that the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

f(x) = \frac{5x}{x - 25}

Considering the denominator, the vertical asymptote is:

x - 25 = 0 -> x = 25.

The horizontal asymptote is found as follows:

y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = \lim_{x \rightarrow \infty} 5 = 5

Hence the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

More can be learned about asymptotes and end behavior at brainly.com/question/28037814

#SPJ1

6 0
2 years ago
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