3r-6=-21
3r-6+6=-21+6 (Add 6 to both sides...)
3r=-15
r=-5
3r-6=21
3r-6+6=21+6 (Add 6 to both sides...)
3r=27
r=9
r=-5 or r=9
Answer:
Hi. I am a math teacher. Your correct answer is 210. You're welcome!
You add eight three times (8+8+8=24)
Answer:
Step-by-step explanation:
First you will divide I-2xI on both sides that should look like this:
-2x/-2 = 10/-2
when you divide it your -2‘s should cancel out and you should be left with
-x=10/-2
when You divide 10/-2 you should get -5
10/-2= -5
your answer should look like this then
-x=-5
-5 is just one of your answers the other is 5
To get rid of the negative on the -X you have to didvide it by both sides
-x/-x=-5/-x
your answer should be
X= 5
your final answers are
-5 or 5
Answer:
That will be;
3x^2 + 5x -6 = 0
Step-by-step explanation:
Here, we want to write 3x^2 + 5x = 6 in the form
ax^2 + bx + c = 0
That will be;
3x^2 + 5x -6 = 0
We can simply get it by bringing the value 6 from the right hand side of the equation to the left hand side of the equation
