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3 years ago

BRAINLIEST OFFER! 7.the probality of winning a game is 25%. How many times would you expect to win if you play 36 times?

Mathematics

1 answer:

PtichkaEL [24]3 years ago

8 0

The answer to 7 is 9 times and the answer to 8 is 248 car owners
Hope this helps

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wel

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1 year ago

Fluency two step equations

marishachu [46]

Answer:

=> 6x-1=5

=>6x=6

=>x=1

5 0

2 years ago

if 7 men and 5 womean have applied for job and 3 applicants are randomly selected from the probability that 2 are men

barxatty [35]

The probability that 2 men are selected is 49/144

Probability is the likelihood or chance that an event will occur.

If 7 men and 5 women have applied for job, the total number of people that applied will be 12 people

Pr(2 men are selected) = 7/12 * 7/12
Pr(2 men are selected) = 49/144

Hence the probability that 2 men are selected is 49/144

Learn more on probabaility here:brainly.com/question/24756209

3 0

2 years ago

Read 2 more answers

Solve the equation 6x+3y=15for y what does y equal if x=2 if x=5

avanturin [10]

6x+3y=15
6*2+3y=15
12+3y=15
3y=3
y=1

6x+3y=15
6*5+3y=15
30+3y=15
3y=-15
y=-5

The answers is y=1 & -5

3 0

3 years ago

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

4 0

11 months ago