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Aleks04 [339]
3 years ago
15

Simone has 5 in her flower shop. Each employee works 6 4/16 hours per day. How many hours in total do the 5 employees work per d

ay?
Mathematics
1 answer:
liq [111]3 years ago
8 0

Answer:

31 1/4 hours

Step-by-step explanation:

Multiply 6 4/16 by 5 which gets you the answer.

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How much is the percent increase from 1 to 4?
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300%

Step-by-step explanation:

3 difference increase

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What is the power notation of 125
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5³

Step-by-step explanation:

125 = 5 × 5 × 5 = 5³

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What is 243 written as a power of a number?
Zigmanuir [339]
A to the power of b

a^b 

a = base

b = exponent

SO

10^243 or 10 to the power of 243.

You can use other numbers also.

Hope i helped!!  
8 0
3 years ago
A large pizza has 16 slices. You eat 4 pieces and 7 chicken wings. What proportion of the pizza did you eat?
ddd [48]

Answer:

4/16

Step-by-step explanation:

You ate 4 slice of the 16 slice pizza

3 0
3 years ago
A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the
Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

P(A) = 0.90*0.03 + 0.1*0.97 = 0.124

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

P(A \cap B) = 0.9*0.03 = 0.027

What is the conditional probability that she does, in fact, have the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0
3 years ago
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