Answer:
Therefore to prove that ABCD is a parallelogram we need,
BK = DK
CK = AK
Step-by-step explanation:
Given:
The diagonals of quadrilateral ABCD , intersect at point K.
To Find:
Which statement needed to prove that ABCD is a parallelogram?
Solution:
For a Quadrilateral to be a Parallelogram,
- Diagonals Bisect each other.
- Opposite Sides are Parallel and Equal.
- Opposite angles are equal.
Here Diagonals intersect at K
∴ BK = DK ......K bisect Diagonal BD
∴ CK = AK ......K bisect Diagonal AC
Therefore to prove that ABCD is a parallelogram we need,
BK = DK
CK = AK
47
Is this it?
1 plus 2(10) plus 8 plus 1(18)
The experimental probability is equal to...
26 / 40
or...
0.65
Let me know if I'm wrong! :D
3 is a set builder of -3,-2,-1,0,1,2
The value of x from the figure is 1 and the equations that represent angle relationships in the figure are 7x + 5x = 3 + 9 and 12x = 12
<h3>Lines and angles</h3>
The point where two lines meet is known as an angle. From the given diagram;
7x-9 = 5x + 3
Determine the value of x
7x + 5x = 3 + 9
12x = 12
x = 12/12
x = 1
Hence the value of x from the figure is 1 and the equations that represent angle relationships in the figure are 7x + 5x = 3 + 9 and 12x = 12
Learn more on lines and angles here: brainly.com/question/25770607
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