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3 years ago

8x^2+16=48 solving quadratic equation

2 answers:

5 0

Take 16 to RHS and then divide by 8 and the result wil 4 .. now take square root.finally you will have 2( positive..negative)

pogonyaev3 years ago

3 0

8x^2+16=48
8x^2+16-16=48-16
8x^2=32
8/8x^2=32/8
x^2=4
square root of x^2=square root of 4
x=2
The value of x is 2

Note: Use the square root symbol where I wrote it in sentence; that is, if you are going to copy this.

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Use the method of undetermined coefficients to find the general solution to the de y′′−3y′ 2y=ex e2x e−x

djverab [1.8K]

I'll assume the ODE is

$y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}$

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$y'' - 3y' + 2y = 0$

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consider the ansatz particular solution

$y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x$

Substituting this into (1) gives

$a(x+2) e^x - 3 a (x+1) e^x + 2ax e^x = e^x \implies a = -1$

For the nonhomogeneous ODE (2),

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take the ansatz

$y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}$

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$b(4x+4) e^{2x} - 3b(2x+1)e^{2x} + 2bxe^{2x} = e^{2x} \implies b=1$

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take the ansatz

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$\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}$

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solniwko [45]

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Step-by-step explanation:

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Sorry if the explanation is a bit confusing but, I used the distance formula to do this.

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I need help with this one to

Aleks [24]

Ok so what you have to do is multiply all the numbers ! Hope this helps so the answer is 127 !

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