Answer:
double the bandwidth assigned per channel to 40 MHz
Explanation:
The best way of doing this would be to double the bandwidth assigned per channel to 40 MHz. This will make sure that the capacity is more than sufficient. This is simply because the bandwidth of a channel represents how much information can pass through the channel at any given second, the larger the channel, the more information/data that can pass at the same time. Therefore, if 20 MHz is enough for the network, then doubling this bandwidth channel size would be more than sufficient capacity for the network to handle all of the data.
Answer:
The answer is below
Explanation :
If a company was using a commercial WAN and a vulnerability appeared that allowed attackers find routing information and therefore be able to eavesdrop on corporate transmissions "It is expected that such a company should try to formulate and establish Virtual Private Networks between corporate sites.
This will ultimately lead to intercepted transmissions to be unreadable. Though such means have been seen as time-consuming."
Answer:
Answer is
By topic, By collection.
Refer below.
Explanation:
Quick SearchLinks to an external site. lets you refine or narrow your search results using links on the right side of the screen. Do a search on wind power. Some criteria that can refine your search results in Quick Search are:
By topic
By collection
Answer:
<em>DBMS Performance
</em>
Explanation:
Database tuning <em>defines a range of activities that are used to maximize and homogenize a database's output.</em>
This typically coincides with query tuning, but applies to database file layout, DBMS software selection, and database environment setup (operating system, CPU).
Database tuning helps to optimize the use of machine resources in order to carry out work as efficiently and quickly as possible.
Many systems are built to handle their use of system resources, but there is still plenty of space for enhancing their performance by tailoring their server and DBMS settings and configuration.
Answer:
int main() {
int _2dArray[32][32];
for (int i = 0; i < 32; i++) {
for (int j = 0; j < 32; j++) {
_2dArray[i][j] = j + i * 32;
}
}
return 0;
}
Explanation:
Here is a generic C/C++ 2d array traversal and main function example. The rest you'll have to figure out based on what kind of app you're making.
Good luck!
