What is Processor to Memory Mismatch problem?

A positive integer is called a perfect number if it is equal to the sum of all of its positive divisors, excluding itself. For e

Ad libitum [116K]

i = 1

while i < 10001:

total = 0

x = 1

while x < i:

if i % x == 0:

total += x

x+=1

if total == i:

print(str(i)+" is a perfect number")

i += 1

When you run this code, you'll see that 6, 28, 496, and 8128 are all perfect numbers.

5 0

3 years ago

Prompt the user to enter a string of their choosing. Output the string. (1 pt) Ex: Enter a sentence or phrase: The only thing we

frosja888 [35]

Answer:

Explanation:

Section 1) Enter String and Output String

#include<iostream> //for input and output

#include <string> // for string

using namespace std;

int main()

{

string sentense;

cout<<"Enter a sentence or phrase: ";

getline(cin,sentense);

cout<<"You Entered :"<<sentense;

return 0;

}

Output

Enter a sentence or phrase: The only thing we have to fear is fear itself

You Entered :The only thing we have to fear is fear itself

Explanation

To get full sentence or phrase, we need to call getline function in string package which will get the overall entered string. cin will not get the whole sentence

Section 2) GetNumOfCharacters

int getNumberOfCharacters(string sentence){

int count =0;

for(int i=0; i<sentence.size(); i++){

count++;

}

return count;

}

Explanation

As we have taken sentence as string in previous section, we need to count total number of characters in the input string. for that purpose we are iterating over all the characters within string through for loop. declaring count variable and initializing it with 0 and increment on every for loop iteration. at the end returning the count variable.

Section 3) Call the GetNumOfCharacters() in main method.

int main()

{

string sentence;

cout<<"Enter a sentence or phrase: ";

getline(cin,sentence);

cout<< getNumberOfCharacters(sentence); //Here we call out method and output its value

return 0;

}

Explanation

In main method first we get the sentence with getline and then by using cout and calling the getNumberOfCharacters(sentence) function it will show the number of characters in string.

Output

Enter a sentence or phrase: The only thing we have to fear is fear itself

45

Section 4) Implement OutputWithoutWhitespace() function

#include<iostream> //for input and output

#include <string> // for string

using namespace std;

int getNumberOfCharacters(string sentence){

int count =0;

for(int i=0; i<sentence.size(); i++){

count++;

}

return count;

}

void OutputWithoutWhitespace(string sentence){

string output="";

for(int i=0; i<sentence.size(); i++){

if(sentence[i]!=' ' && sentence[i] != '\t'){ // checking the tab and spaces

output+=sentence[i]; //then add that into output string

}

cout<< output;

}

int main()

{

string sentence;

cout<<"Enter a sentence or phrase: ";

getline(cin,sentence);

OutputWithoutWhitespace(sentence);

return 0;

}

Code Explanation

In OutputWithoutWhitespace() function we get string as a parameter and iterating all the characters and if current iteration character from sentence string is not equal to tab('\t') and space then add that character into output string. After the loop is finished, output the result.

Output

Enter a sentence or phrase: The only thing we have to fear is fear itself hello

Theonlythingwehavetofearisfearitselfhello

7 0

3 years ago

Exercise1 : Defining Circle type and Creating a Driver Circle class private members double radius double xPos double yPos public

asambeis [7]

Answer:

Aee explaination

Explanation:

1) class_circle.h

#include<iostream>

#include<cmath>

#include<iomanip>

#define PI 3.14159

using namespace std;

class circle

{

private:

double radius,xPos,yPos;

public:

double diameter();

double area();

double circumference();

double getRadius();

double getX();

double getY();

void setX(double x);

void setY(double y);

double distanceToOrigin();

bool intersect(const circle& otherCircle);

bool setRadius(double r);

};

class CircleDriver:public circle

{

private:

circle circ1;

circle circ2;

void obtainCircles();

void printCircleInfo();

public:

void run();

};

2) class_circle.cpp

#include "class_circle.h"

double circle::diameter()

{

return (radius * 2);

}

double circle::area()

{

return PI * radius * radius;

}

double circle::circumference()

{

return 2 * PI * radius;

}

double circle::distanceToOrigin()

{

return sqrt((xPos * xPos) + (yPos * yPos));

}

double circle::getRadius()

{

return radius;

}

double circle::getX()

{

return xPos;

}

double circle::getY()

{

return yPos;

}

void circle::setX(double x)

{

xPos = x;

}

void circle::setY(double y)

{

yPos = y;

}

bool circle::setRadius(double r)

{

if(r > 0)

{

radius = r;

return true;

}

else

{

radius = 0;

return false;

}

bool circle::intersect(const circle& otherCircle)

{

double dist1 = (radius - otherCircle.radius) * (radius - otherCircle.radius);

double dist2 = ((xPos - otherCircle.xPos) * (xPos - otherCircle.xPos)) + ((yPos - otherCircle.yPos)*(yPos - otherCircle.yPos));

double dist3 = (radius + otherCircle.radius) * (radius + otherCircle.radius);

if((dist1 <= dist2 ) && (dist2 <= dist3) && (dist1 < dist3))

return true;

else

return false;

}

void CircleDriver::obtainCircles()

{

double x,y,rad;

cout<<"Enter xPos yPos circle 1 :";

cin>>x>>y;

do

{

cout<<"\n\nEnter radius for circle 1 :";

cin>>rad;

}while(rad <= 0);

circ1.setX(x);

circ1.setY(y);

circ1.setRadius(rad);

cout<<"\n\nEnter xPos yPos circle 2 :";

cin>>x>>y;

do

{

cout<<"\n\nEnter radius for circle 2 :";

cin>>rad;

}while(rad <= 0);

circ2.setX(x);

circ2.setY(y);

circ2.setRadius(rad);

}

void CircleDriver::printCircleInfo()

{

cout<<setprecision(6)<<endl;

cout<<"\n\nInformation for Circle 1:"<<endl;

cout<<"location:( "<<circ1.getX()<<" ,"<<circ1.getY()<<" )"<<endl;

cout<<"diameter: "<<circ1.diameter()<<endl;

cout<<"area: "<<circ1.area()<<endl;

cout<<"circumference: "<<circ1.circumference()<<endl;

cout<<"distance from the origin: "<<circ1.distanceToOrigin()<<endl;

cout<<"\n\nInformation for Circle 2:"<<endl;

cout<<"location:( "<<circ2.getX()<<" ,"<<circ2.getY()<<" )"<<endl;

cout<<"diameter: "<<circ2.diameter()<<endl;

cout<<"area: "<<circ2.area()<<endl;

cout<<"circumference: "<<circ2.circumference()<<endl;

cout<<"distance from the origin: "<<circ2.distanceToOrigin()<<endl<<endl;

if(circ1.intersect(circ2))

cout<<"The circles intersect."<<endl;

else

cout<<"The circles does not intersect."<<endl;

}

void CircleDriver::run()

{

obtainCircles();

printCircleInfo();

}

3) main.cpp

#include "class_circle.h"

int main()

{

CircleDriver myDriver;

myDriver.run();

return(0);

}

Please refer below output for reference

Enter xPos yPos circle 1 :0.0 50.0

Enter radius for circle 1 :100.0

Enter xPos yPos circle 2 :50.0 0.0

Enter radius for circle 2 :100.0

Information for Circle 1:

location:( 0 ,50 )

diameter: 200

area: 31415.9

circumference: 628.318

distance from the origin: 50

Information for Circle 2:

location:( 50 ,0 )

diameter: 200

area: 31415.9

circumference: 628.318

distance from the origin: 50

The circles intersect.

Process returned 0 (0x0) execution time : 18.245 s

Press any key to continue.

8 0

3 years ago

Jerry is having trouble finding the information that he needs from his search results. Which technique would you suggest he use

andrew-mc [135]

Put parentheses around keywords

8 0

3 years ago

Read 2 more answers

Hello join please I would be so happy if y’all did

Luda [366]

Answer:

i bet its a class raid

Explanation:

its gonna be a class raid

8 0

2 years ago

Read 2 more answers