Answer:
The description for the given question is described in the explanation section below.
Explanation:
Since deviance constitutes a breach of a people's current standard. I believe Erickson's psychological concept that Deviance becomes a trait that is commonly considered to need social control agencies' intervention, i.e. 'Something must being done'.
- There most probably resulted whenever the rules governing behavior appear inconsistent in just about any particular frame.
- Therefore the principle of this theory is that even in the analysis of deviance this same significant point seems to be the social community, instead of the participant.
Answer:
Secure is the correct answer for the above question.
Explanation:
- When any person wants that any information is not hacked by any user then he needs to secure the information with the help of any security mechanism. This security mechanism can be of any type that facilities the user to stop the information are being hacked.
- The above question asked about the work which is needed to stop the message is being hacked. So there is a need to secure the information. so secure is the correct option while the other option is not valid because "simple, economical or verifiable" can not stop the message from accessed by the unauthorized user.
Answer:
The answer is Upload bandwidth
Explanation:
Bandwidth refers to the highest transfer rate of data on an internet connection or network.
Upload bandwidth is the amount of data that moves from a computer to the internet or a network within a given amount of time. Documents, music files, video files, software and so on can be uploaded to the internet or a network.
I have roblox and I would like to be friends on it
Answer:
The recursion function is as follows:
def raise_to_power(num, power):
if power == 0:
return 1
elif power == 1:
return num
else:
return (num*raise_to_power(num, power-1))
Explanation:
This defines the function
def raise_to_power(num, power):
If power is 0, this returns 1
if power == 0:
return 1
If power is 1, this returns num
elif power == 1:
return num
If otherwise, it calculates the power recursively
else:
return (num*raise_to_power(num, power-1))
