HELP ME PLEASE HELP ME!

2 answers:

8 0

The chance of picking a almond cookie the first time:
you have 6 cookies, 3 of them are almond
So the chance of taking an almond cookie is
$\frac{3}{6} = \frac{1}{2}$
The second time there are 5 cookies left, 2 of them are almond cookies
The chance of taking an almond cookie is
$\frac{2}{5}$
To know the probability of picking two almond cookies in a row, multiply the changes:
$\frac{1}{2} \times \frac{2}{5} = \frac{1}{5}$
The chance of taking two almond cookies is 1/5

choli [55]2 years ago

7 0

1/5 is the probability

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Jane buys a coat that is $18 off the orinigal price. This is a 30% discount. What is the original price of the coat?

mylen [45]

Total cost - (total cost * 30%) = discounted price
$C - .3C = 18 \\ 
.7C =18 \\
C = \frac{18}{ \frac{7}{10}}\\
C=\frac{180}{7}\\
C= 25.7142857...$

6 0

3 years ago

Mariam’s uncle donate 120 cans of juice and 90 packs of cheese cracker for the school picnic. Each student must receive the same

monitta

Answer:

8 students,

15 cans of juice and 11 packs of cheese cracker

Step-by-step explanation:

Mariam’s uncle donate 120 cans of juice and 90 - 2 = 88 packs of cheese cracker (eats two packs) for the school picnic.

Factor these numbers:

$120=2\cdot 60=2\cdot 2\cdot 30=2\cdot 2\cdot 2\cdot15=2\cdot 2\cdot 2\cdot 3\cdot 5\\ \\88=2\cdot 44=2\cdot 2\cdot 22=2\cdot 2\cdot 2\cdot 11$

The greatest common factor is

$2\cdot 2\cdot 2=8,$

so the greatest number of students who can share the food equally is 8 and each student will get $3\cdot 5=15$ cans of juice and 11 packs of cheese cracker.