Ask question

Ask question

All categories

3 years ago

7

Tickets to a school basketball game cost $4 for students and $7 for adults. At the end of the night, 168 tickets are sold for a

total of $861. How many student tickets are sold?
A.
29

B.
63

C.
105

D.
42

2 answers:

Alex_Xolod [135]3 years ago

8 0

Answer: c

Step-by-step explanation:

105 x 4 = 420

63 x 7 = 441

420 + 441 = 861

Luba_88 [7]3 years ago

5 0

Answer: C because of process of elimination

You might be interested in

Of the 800 participants in a marathon 220 are running to raise money for a cause. How many participants out of 100 are running f

nadezda [96]

Answer:

27.5 /100 are running for a cause

Step-by-step explanation:

We know that 220/800 are running for a cause

Divide the top and bottom by 8 to get the fraction out of 100

220 /8 =27.5

800/8 = 100

27.5 /100 are running for a cause

7 0

2 years ago

In lancaster, the library is 9 miles due south of the courthouse and 4 miles due west of the

skad [1K]

use brainly to find the answer

8 0

2 years ago

The number of students in a school is about 13⁴. How many students does this expression represent?

andrew-mc [135]

Answer:

28,561

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Wyatt makes and sells rope doormats. He uses 200 feet of rope for each doormat. He wants to make 25 doormats. Which expression s

olga_2 [115]

Answer: See explanation

Step-by-step explanation:

First and foremost, we should not that:

1 yard = 3 feet

We are informed that Wyatt uses 200 feet of rope for each doormat and that he wants to make 25 doormats.

The expression that shows a correct way to find how many yards of rope he needs will be:

= (200 × 25) / 3

= 5000/3

= 1666.67 yards

4 0

2 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago