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Serga [27]
3 years ago
10

What is the fraction of six and two thirds percent?

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

The fraction of six and two-thirds percent is \frac{1}{15}

Step-by-step explanation:

Given:

The percent whose fraction is required is given as:

6\frac{2}{3}\%

A percentage can be converted by dividing it by 100.

Here, first we need to convert the mixed fraction into improper fraction.

We can do so by multiplying the whole part of the mixed fraction to the denominator and then adding the numerator to the result.

So, 6\frac{2}{3}=\frac{6\times3+2}{3}=\frac{20}{3}

Now, dividing the improper fraction by 100 to remove the percentage, we get:

=\frac{20}{3}\div 100\\=\frac{20}{3}\times \frac{1}{100}\\=\frac{20\times1}{3\times 100}\\=\frac{20}{300}\\=\frac{1}{15}(As\ 20/20=1\ and\ 300/20=15)

Therefore, the fraction of six and two-thirds percent is \frac{1}{15}

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A box contains 2 red marbles , 3 green marbles , and 3 blue marbles
krek1111 [17]

Answer:

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Step-by-step explanation:

no question?

5 0
4 years ago
For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

r = 27

The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

5 0
3 years ago
PLEASE HELP, I’LL GIVE BREAINLIST!
zzz [600]

Answer:

1/72

Step-by-step explanation:

Not entirely sure but i do hope it helps

5 0
4 years ago
Read 2 more answers
THIS IS MY LAST QUETSION!!!! Please help!!!
DedPeter [7]

Answer:

x=19(rounded) or 18.7882942281

Step-by-step explanation:

a^2+b^2=C^2

8^2+17^2=C^2

64+289= C^2

353=C^2

\sqrt{353} =\sqrt{C^2}\\

18.7882942281= C

19= C

7 0
3 years ago
Expand 3(x+ 2.3) <br> Expand 1/3(9x-12)
Snezhnost [94]

Answer:

3x+6.9 and 3x-4

Step-by-step explanation:

since 3 x x is 3x and the sign in the bracket is addition you place it there then place 3 x 2.3

being 6.9.

1/3 x 9is 9/3 and 3 can multiply both sides to get 3/1 or 3 then bring the minus and 1/3 x 12 is 12/3 3 can multiply both sides to get 4/1 or 4

4 0
3 years ago
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