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IrinaK [193]
3 years ago
15

Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the

specified axis. y = 7 x , y = 0, x = 1; about x = −4

Mathematics
1 answer:
insens350 [35]3 years ago
6 0

Answer:

So, the volume V is

V=\frac{14\pi}{3}

Step-by-step explanation:

We have that:

y=7x\\\\y=0\\\\x=1\\\\x=-4\\

We have the formula:

V=2\pi\int_a^b x(g(x)-f(x))\, dx\\\\g(x)>f(x).

We calculate the volume V, we get

V=2\pi\int_a^b x(g(x)-f(x))\, dx\\\\V=2\pi\int_0^1 x(7x-0)\, dx\\\\V=2\pi\int_0^1 7x^2\, dx\\\\V=2\pi\cdot 7\left[\frac{x^3}{3}\right]_0^1\\\\V=14\pi\left(\frac{1}{3}-\frac{0}{3}\right)\\\\V=\frac{14\pi}{3}

So, the volume V is

V=\frac{14\pi}{3}

We use software to draw the graph.

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\text{Use the Pythagorean theorem:}\\\\r-hypotenuse\\\\r^2=7^2+5^2\\\\r^2=49+25\\\\r^2=74\to r=\sqrt{74}

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D.\\\sin\theta=\dfrac{2}{3}\\\\\sin^2\theta+\cos^2\theta=1\to\left(\dfrac{2}{3}\right)^2+\cos^2\theta=1\\\\\dfrac{4}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{4}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{5}{9}\to\cos\theta=\sqrt{\dfrac{5}{9}}\to\cos\theta=\dfrac{\sqrt5}{3}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\to\tan\theta=\dfrac{\frac{2}{3}}{\frac{\sqrt5}{3}}=\dfrac{2}{3}\cdot\dfrac{3}{\sqrt5}=\dfrac{2}{\sqrt5}=\dfrac{3\sqrt5}{5}

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