Which answer is the correct “reason” for step 1?

Write the explicit formula

mixas84 [53]

Answer:

The required explicit formula is A(n)= 4-4n

10th term of arithmetic sequence is (-36)

Step-by-step explanation:

Given arithmetic sequence is 8,4,0,-4,-8......

The arithmetic sequence is given by a,a+d,a+2d.......a+(n-1)d

Comparing both the sequence we get,

a=8 and a+d=4

For value of d:

d+a=4

d=4-8=(-4)

The explicit formula is given by : A(n)= a+(n-1)d

A(n)= a+(n-1)d

A(n)= 8+(n-1)(-4)

A(n)= 8-4n+4

A(n)= 4-4n

Therefore, The required explicit formula is A(n)= 4-4n

To find value of 10 th term:

Take n=10 in explicit formula

A(10)= 4-4(10)

A(10)= -36

Therefore, 10th term is (-36)

8 0

3 years ago

Joel needs 785 tickets to get the prize he wants at the arcade. He already has 284 tickets and can earn 35 tickets each time he

Cloud [144]

He needs to play 23 more times. 785 / 35 = 23

He will have extra points but it will be enough to get the prize.

4 0

3 years ago

What is the polynomial of f(x) of a degree of 3 that has the following zeros?

makvit [3.9K]

Answer:

Id

Step-by-step explanation:

8 0

3 years ago

Joey's science class has between 18 and 41 students. Exactly 2/3 of the students in his class got an A on the exam, and exactly

xz_007 [3.2K]

Heyyyyyyyyyy

C is the answer

6 0

3 years ago

A study1 conducted in July 2015 examines smartphone ownership by US adults. A random sample of 2001 people were surveyed, and th

dusya [7]

Answer:

a) Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

b) $z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679$

c) $z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58$

d) For this case we see that $\hat p_1 > \hat p_2$ so then the answer for this cae would men

Step-by-step explanation:

Information given

$X_{1}=688$ represent the number of men with smartphone

$X_{2}=671$ represent the number of women with smartphone

$n_{1}=989$ sample of men selected

$n_{2}=1012$ sample of women selected

$p_{1}=\frac{688}{989}=0.696$ represent the proportion of men with smartphone

$p_{2}=\frac{671}{1012}=0.663$ represent the proportion of women with smartphone

$\hat p$ represent the pooled estimate of p

z would represent the statistic

$p_v$ represent the value

Part a

We want to test if we have difference in the proportion owning a smartphone between men and women, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

Part b

The statistic for this case is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679$

Part c

Replacing the info given we got:

$z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58$

Part d

For this case we see that $\hat p_1 > \hat p_2$ so then the answer for this cae would men

4 0

3 years ago