Answer:
If we have a set of N elements:
{x₁, x₂, ..., xₙ}
The mean value (also called the average value) Is calculated as:
Average = (x₁ + x₂ + ... + xₙ)/n
So if x is the average of 13, -16 and 6 ( a total of 3 values)
x will be equal to:
x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1
x = 1
And we know that:
y = ∛8
Remember that:
2*2 = 4
and
4*2 = 8
then
2*2*2 = 2^3 = 8
then ∛8 = 2.
So we have:
y = ∛8 = 2
Now we can replace these values in the equation:
x^2 + y^3
replacing:
x = 1
y = 2
we get:
1^2 + 2^3 = 1 + 8 = 9
Answer:
Step-by-step explanation:
In Δ AFB,
∠AFB + ∠ABF + ∠A = 180 {Angle sum property of triangle}
90 + 48 + ∠1 = 180
138 + ∠1 = 180
∠1 = 180 - 138
∠1 = 42°
FC // ED and FD is transversal
So, ∠CFD ≅∠EDF {Alternate interior angles are congruent}
∠2 = 39°
In ΔFCD,
∠2 + ∠3 + ∠FCD = 180
39 + ∠3 + 90 = 180
129 +∠3 = 180
∠3 = 180- 129
∠3 = 51°
