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Aleks [24]
3 years ago
14

A number b minus 4.2 is less than −7.5

Mathematics
2 answers:
Kruka [31]3 years ago
5 0
B - 4.2 < -7.5
subtract b and 4.2 
less then sign is <
then <-7.5
lina2011 [118]3 years ago
5 0

Answer:

Given: A number b minus 4.2 is less than -7.5.

Here, b is the number.

"less than" symbol is represented by '<'

"minus" means subtract.

"b minus 4.2" translated to  b - 4.2

Then, our inequality becomes;

b - 4.2 < -7.5

To solve for b;

Add 4.2 both sides we get;

b -4.2 + 4.2 < -7.5 + 4.2

Simplify:

b < -3.3

Therefore, an inequality for the given word sentence is,  b - 4.2 < -7.5




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A random sample of 9 fields of corn has a mean yield of 40.6 bushels per acre and standard deviation of 7.52 bushels per acre. D
zaharov [31]

Answer:

The critical value that should be used in constructing the confidence interval is -1.397 and 1.397.

80% confidence interval for the true mean yield is [37.1 bushels per acre, 44.1 bushels per acre].

Step-by-step explanation:

We are given that a sample of 1584 third graders, the mean words per minute read was 35.7. Assume a population standard deviation of 3.3.

Firstly, the pivotal quantity for 80% confidence interval for the true mean is given by;

                          P.Q. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean yield = 40.6 bushels per acre

            s = sample standard deviation = 7.52 bushels per acre

            n = sample of fields of corn = 9

            \mu = true mean yield

<em>Here for constructing 80% confidence interval we have used One-sample t test statistics as we don't know about the population standard deviation.</em>

<em />

<u>So, 99% confidence interval for the true mean yield, </u>\mu<u> is ;</u>

P(-1.397 < t_8 < 1.397) = 0.80  {As the critical value of t at 8 degree of

                                            of freedom are -1.397 & 1.397 with P = 10%}  

P(-1.397 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.397) = 0.80

P( -1.397 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.397 \times {\frac{s}{\sqrt{n} } } ) = 0.80

P( \bar X-1.397 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.397 \times {\frac{s}{\sqrt{n} } } ) = 0.80

<u>80% confidence interval for</u> \mu = [ \bar X-1.397 \times {\frac{s}{\sqrt{n} } } , \bar X+1.397 \times {\frac{s}{\sqrt{n} } } ]

                                                = [ 40.6-1.397 \times {\frac{7.52}{\sqrt{9} } } , 40.6+1.397 \times {\frac{7.52}{\sqrt{9} } } ]

                                                = [37.1 , 44.1]

Therefore, 80% confidence interval for the true mean yield is [37.1 bushels per acre, 44.1 bushels per acre].

7 0
3 years ago
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