2 consecutive odd integers : x and x + 2
x(x + 2) = 27 + 6(x + x + 2)
x^2 + 2x = 27 + 6(2x + 2)
x^2 + 2x = 27 + 12x + 12
x^2 + 2x - 12x - 12 - 27 = 0
x^2 -10x - 39 = 0
(x + 3)(x - 13) = 0
x + 3 = 0
x = -3 (extraneous solution)
x - 13 = 0
x = 13
x + 2 = 15
so ur 2 integers are 13 and 15, with 15 being the largest
The answer is 107
Vote Trump 2020
Answer:
35
Step-by-step explanation:
this is a right triangle g+55 is a right triangle as shown by the red square in the corner.
90-55=35
so g=35
Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer
Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
-2x - 6. -2x -6
0 = x^2 + 3x. Factor
0 = x (x + 3)
Solve: x = 0. x + 3 = 0. ——> x = -3. Substitute into one original equation to get y value for
y = 2x + 6.
y = 2(0) + 6. y = 2(-3) + 6
y = 6. y = -6 + 6 —-> y = 0
(0 , 6) And. (-3 , 0)
The first choice if ()2 means to the power of two if not then it is none of them.