So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)
Hope this helps!
Honestly, I don’t really know but I believe it’s 3
Answer:
Please see the attached images for explanation:
Step-by-step explanation:
Please let me know if you have any questions :)
Answer
Step-by-step explanation:
The slope intercept form for a line is y = mx + b.
↑ <span>↑
m is the slope of the line or how steep it is. b is where the line runs into the y axis at one point. x and y are the values you plug in when you have a specific point you want to use (x, y).
For the first picture, you can see that the line "intercepts" or collides with the y axis at 1. Thus we know the b value.
To find the slope, you just pick 2 points on the line and plug them into a little equation (try to memorize this equation, it helps to find slope):
m = (y</span>₂ - y₁)/(x₂ - x₁)
The two points we'll use are (1, 0) and (0, 1) since x goes through both of
those points. ↑ ↑ ↑ ↑
x₁ y₁ x₂ y<span>₂
m = (1 - 0)/(0 - 1)
m = 1 / -1
m = -1
This makes sense - since the slope is going downward, the slope is negative.
So the equation is:
y = -x + 1
____________________________________________________________
For the second problem, We can see the line intercepts the y-axis at -5. That is our b value.
The the slope of this line is 0 since it is not going up or down, so that is our m value:
y = 0(x) - 5 = -5
The equation of the line is y = -5</span>
