Answer: The total interest paid on the mortgage is $179550
Step-by-step explanation:
The initial cost of the property is $300000. If he deposits $30000, the remaining amount would be
300000 - 30000 = $270000
Since the remaining amount was compounded, we would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 270000
r = 2% = 2/100 = 0.02
n = 12 because it was compounded 12 times in a year.
t = 25 years
Therefore,
A = 270000(1+0.02/12)^12 × 25
A = 270000(1+0.0017)^300
A = 270000(1.0017)^300
A = $449550
The total interest paid on the mortgage is
449550 - 270000 = $179550
Answer:
(2, 1 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( 
, 
)
Here (x₁, y₁ ) = (7, 3) and (x₂, y₂ ) = (- 3, - 1) , then
midpoint = ( 
, 
) = ( 
, 
) = (2, 1 )
Sin 3θ = 0
3θ = sin^-1 0 = nπ
θ = nπ/3
Answer:
34%
Step-by-step explanation:
Given that the distribution of daily light bulb request replacement is approximately bell shaped with ;
Mean , μ = 45 ; standard deviation, σ = 3
Using the empirical formula where ;
68% of the distribution is within 1 standard deviation from the mean ;
95% of the distribution is within 2 standard deviation from the mean
Lightbulb replacement numbering between ;
42 and 45
Number of standard deviations from the mean /
Z = (x - μ) / σ
(x - μ) / σ < Z < (x - μ) / σ
(42 - 45) / 3 = -1
This lies between - 1 standard deviation a d the mean :
Hence, the approximate percentage is : 68% / 2 = 34%
