Answer:
A. Glucose:
As lactose is absent will follow the glucose metabolism, so the lac repressor will hold tightly with the operator which leads to the prevention of transcription as RNA polymerase can not bind to promoter so no lactose metabolism.
B. lactose:
In the case or wild mutant lactose metabolism will occur as lactose is present, allolactose binds to the lac repressor thus the operator and promoter are free so transcription starts. The same result will be in all test except in the case of a mutant repressor.
C. glucose and lactose:
In this case, diauxic growth will occur. This growth takes place when two sugars are present in the media. The preferred sugar will be consumed first That is glucose. Then a lag phase will come which will be followed by the second sugar metabolism that is lactose. the given two cases :
Lactose will be metabolized first, as operator site mutation prevents repressor protein binding and thus will lead to the constitutive synthesis of lac operon in test B.
The same thing will happen, as in this case also, constitutive synthesis of lac operon will happen in test C.
Cultures grown in the presence of both glucose and lactose are metabolizing lactose. In the test (b) and (c) will be responsible due to constitutive synthesis of lac operon will happen.
The <em>independent </em>variable is the variable that you change and control in your experiment. The <em>dependent</em> variable is the one you don't have control over and is affected by how the independent variable reacts.
For Example:
Let's say you're doing an experiment seeing how different sugars affect the density of cupcakes. The type of sugar you add would be the independent variable, because you are choosing it. The density would be the dependent variable, since it depends on the sugar used.
The answer is fusion of gametes via fertilization.
Answer:
125.6
Explanation:
Area of a circle = πr^2
Area of circle 1 = 3.14 × 11 × 11
=379.94cm^2
Area of circle 2= 3.14 × 9 ×9
=254.64cm^2
Area of a shaded region
=379.94cm^2 - 254.64cm^2
=125.60cm^2
<span>The water diffuses out of the cell to equalize the solute concentrations
Salt is too big to pass through the cell and water is the only so water tries to "balance" the concentration on the inside and outside.
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