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LenKa [72]
3 years ago
8

Trevin puts 8 gallon of gas

Mathematics
2 answers:
Citrus2011 [14]3 years ago
5 0

Answer:

good for trevin?

Step-by-step explanation:

we'll need more to go on haha

Savatey [412]3 years ago
4 0

Answer:

Trevin puts 8 gallons of gas in his car and pays $22. The cost of 9 gallons of gas at this rate is $24.75

Step-by-step explanation:

hope this helps

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CAN ANYONE ANSWER THIS CORRECTLY???
Alisiya [41]
B, D, E are appropriate choices.

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A ray can be named by its (one) end-point and any other point on the ray. Since there are an infinite number of points on the ray, it can be named an infinite number of ways.
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3 years ago
A coin sorting machine can sort a certain number of coins in 15 min a second machine can sort the same number of coins in 30 min
padilas [110]

Answer:

10 minutes

Step-by-step explanation:

Let's use the variable x for the amount of coins.

The first machine can sort x coins in 15 minutes, so its speed is x/15 coins/minute.

The second machine can sort x coins in 30 minutes, so its speed is x/30 coins/minute.

If we sum the speeds, we have that the speed will be:

speed = (x/15) + (x/30) = (2x + x)/30 = 3x/30 = x/10

The total speed can sort x/10 coins per minute, that is x coins in 10 minutes.

7 0
3 years ago
A recently discovered planet rotates 250 times on its axis in 15 months. At this rate, how many times will the planet rotate in
Stella [2.4K]

Answer:

H:150

Step-by-step explanation:

you divide 250 by 15 to get the amount of rotations per month, then once you get that answer which is 16.6666667, you then multiply that number by 9 and there is your answer

6 0
3 years ago
Under a dilation of a scale factor 4 with the center at the origin, if A (3,5), what will be the coordinates of the point A'
cupoosta [38]
A'=(3\cdot4,5\cdot4)\\
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7 0
3 years ago
| x-3 | &lt; x-3<br><br> can someone give a step by step process on how to do this?
statuscvo [17]

Answer:

There are no solutions to the inequality.

Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)  

2. Solve each equation separately

(a) Equation (1)

\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}

(b) Equation (2)

\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &

For example, if x = 0, we get  

|0 - 3| < 0 - 3 or

3 < -3

4 0
3 years ago
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