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3 years ago

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blsea [12.9K]3 years ago

6 0

$\cfrac{a}{sinA}= \cfrac{b}{sinB} \ \ \to \\ sinB= \cfrac{b*sinA}{a} = \cfrac{14*sin35^o}{12}= 0.6692 \ \ \to \ m \angle B=42^o \\ \\ \\ m \angle C=180- m \angle A- m \angle B=180-35-42=103^o \\ \\ \\ \cfrac{a}{sinA}= \cfrac{c}{sinC} \ \ \to \ c= \cfrac{a*sinC}{sinA}= \cfrac{12*sin103^o}{sin35^o} \approx 20.4$

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