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Roman55 [17]
2 years ago
12

Can someone help me solve this question please?

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

To find the population after a year, you can multiply 4.5x10⁸ by 1.05, as it increases by 5% per year (1.05=1+5%). To find the population after five years, you have to multiply 4.5x10⁸ by 1.05 five times.

4.5x10⁸(1.05)⁵

=574326703.125

Since you can't have a decimal amount of people, you round this number to 574326703.

Therefore, the population after five years is going to be about 574326703.

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Solve the equation. If necessary, round your answer to the nearest tenth.
Agata [3.3K]
B: x = 5.5 or -5.5 (square root) -> 2x = 11 (divide by 2) -> x = 5.5 or -5.5
6 0
3 years ago
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Convert 657 as binary form in computer language​
Monica [59]

Answer:

1010010001

Step-by-step explanation:

Keep dividing 657 by 2, and record the quotient and remainder

657

328,1

164,0

82,0

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20,1

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5,0

2,1

1,0

So chain the remainders from bottom up to get the binary number:

1010010001

Check:

1+16+128+512=657  checks.

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2 years ago
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nata0808 [166]
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3 years ago
The difference between 8 and a number is 5.
pav-90 [236]

Answer:

the answer is 3.

Step-by-step explanation:

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3 0
2 years ago
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In 2013 number of students in a small school is 284.it is estimated that student population will increase by 4 percent
BaLLatris [955]

The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.

Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get

{P}_{n} =284\cdot {1.04}^{n}P

n

=284⋅1.04

n

We can find the number of years since 2013 by subtracting.

\displaystyle 2020 - 2013=72020−2013=7

We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.

\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P

7

=284⋅1.04

7

≈374

The student population will be about 374 in 2020.

5 0
2 years ago
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