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Bad White [126]
3 years ago
8

Is this graph a function or not a function?

Mathematics
2 answers:
Murrr4er [49]3 years ago
7 0

Answer:

Not a Function

Step-by-step explanation:

It failed the Vertical line test.

fiasKO [112]3 years ago
5 0

Answer:

Not a function.

Step-by-step explanation:

It doesn't pass the vertical line test since its a circle, meaning that it's not a function.

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F(x) = 3x-1 , (f of g)(x) = x^2 , Find g(x)
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Answer:

g(x)=\dfrac{x^2+1}{3}

Step-by-step explanation:

<u>Given functions</u>:

\begin{cases}f(x)=3x-1\\(f \circ g)(x)=x^2\end{cases}

Composite functions are when the <u>output</u> of one function is used as the <u>input</u> of another.

Therefore, the given <u>composite function</u> (f o g)(x) means to <u>substitute</u> function g(x) in place of the x in function f(x).

\begin{aligned}(f \circ g)(x) & = x^2\\f(g(x)) & = x^2\\\implies 3(g(x))-1 & = x^2\\3(g(x))-1+1 & = x^2+1\\3(g(x))&=x^2+1\\\dfrac{3(g(x))}{3}&=\dfrac{x^2+1}{3}\\\implies g(x)&=\dfrac{x^2+1}{3}\end{aligned}

Therefore:

\boxed{g(x)=\dfrac{x^2+1}{3}}

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