The two quadrilaterals are given similar .
In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .
The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC
We can form a proportion with the proportional sides:
![\frac{16}{x} =\frac{12}{18}](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%7D%7Bx%7D%20%3D%5Cfrac%7B12%7D%7B18%7D%20%20)
To solve for x we cross multiply
12x=(16)(18)
12x=288
Dividing both sides by 12 we get
x=24.
The second longest side of quadrilateral EFGH is 24 ft.
Answer:
C
Step-by-step explanation:
Easiest way is algebra so
x+y are 2 numbers
if (x+y)/2=44
and x or y=12 (pic one)
so if x=12
subsitute
(12+y)/2=44
multiply both sdies by 2 to clear fraction
12+y=88
subtract 12 from both sides
y=76
the numbers are 12 and 76
5x-29>-34
5x>-5
x>-1
x<1
2x+31<29
2x<-2
x<-1
x>1
They must make up their mind. Either they should never, or else they should always.