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Andrei [34K]
3 years ago
9

I NEED HELP SOMEONE PLEASE HELP ME

Mathematics
1 answer:
Amanda [17]3 years ago
6 0

Answer:

27.3

Step-by-step explanation:

The base of the triangle is,

√(12²-5²)

= √119 = 10.9

The area of the triangle,

5×10.9/2

= 109/4 = 27.25 ≈ 27.3

Answered by GAUTHMATH

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Step-by-step explanation:


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What are the coordinates of the point that is common to the graph of f(x) = (2/3) ^ x and the graph of f(x) = (3/2) ^ x
kiruha [24]

Answer:

Both point are y=0. The difference between the two is that 2/3 is always decressing and 3/2 is always incressing.

Step-by-step explanation:

7 0
3 years ago
Hi so this question is super confusing! I can't even figure it out
frutty [35]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
For what value of x does the function have an output of -7, given that g(x) = -3x + 8
madam [21]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Look at the graph shown below:
ElenaW [278]
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 0}}\quad ,&{{ 4}})\quad 
%   (c,d)
&({{ -4}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-4}{-4-0}

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=0\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}

once you get the slope and solve for "y", that'd be the equation of the line.
7 0
3 years ago
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