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beks73 [17]
3 years ago
6

6 less than r ?????????????

Mathematics
2 answers:
ollegr [7]3 years ago
8 0

Answer: 6-R

Step-by-step explanation:

hjlf3 years ago
6 0

Answer:

Step-by-step explanation:

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Answer:

y= 25x+500

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3 years ago
Solve the iniquality 6x - 8 > 4x + 26
lesya692 [45]

Answer:

x > 17

Step-by-step explanation:

Add 8 to both sides:

6x - 8 > 4x + 26

6x > 4x + 34

Subtract 4x from both sides:

2x > 34

Divide each side by 2:

x > 17

So, the solution is x > 17

7 0
3 years ago
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Sarah makes 1/2 pound of caramel popcorn and puts it in a bag that holds 1/8 of a pound. Which equation can be used to find how
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Step-by-step explanation: I hope this helped!

7 0
3 years ago
Use a minimum of two sentences to describe the process for writing the ln(x)=2 in exponential form.
attashe74 [19]

Recall that ln(x)=log_e

Also recall that log_a(b)=c translates to a^c=b

Therefore, ln(x)=2 is log_e(x)=2 which is e^2=x

4 0
3 years ago
Two different samples will be taken from the same population of test scores where the population mean and standard deviation are
Rom4ik [11]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

<em>n</em>₁ = 25

<em>n</em>₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

  • Width for <em>n</em> = 25:

        \text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\ [2\cdot z_{\alpha/2}\cdot \sigma]

  • Width for <em>n</em> = 64:

        \text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\ [2\cdot z_{\alpha/2}\cdot \sigma]

Thus, the sample consisting of 64 data values would give a greater precision.

3 0
3 years ago
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