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Genrish500 [490]
3 years ago
6

Add the product of 5 and 6 with the product of 3 and 7

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
5 0

It is 51.                                           

5x6=30

3x7=21

30+21=51

Hope that I was of help.

pav-90 [236]3 years ago
4 0
30 plus 21 equals 51.
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Harry owes the bank money. To repay his debt, he paid $150 back to the bank each month. After 10 months, his remaining debt was
ira [324]
If you have paid back 150 a month you multiply by 10 then you subtract $6900, your remaining balance is $5,400. Good luck with your equation.
8 0
3 years ago
If a new soccer ball is labeled $45, what would the new price be if the sign above it says "63% off"?
Paul [167]

Answer:

New price of the ball after discount = $16.65

Step-by-step explanation:

Selling price of the soccer ball = $45

Discount labeled on the ball = 63% off

Therefore, selling price after the discount = Original selling price - %discount

= $45 - (63% of $45)

= $45 - $28.35

= $16.65

New price of the ball after discount = $16.65

3 0
2 years ago
How much time is in between these two times?<br><br> Start: 11:34 A.M.<br><br> End: 10:23 P.M.
icang [17]
10 Hours and 49 Minutes. 
4 0
3 years ago
Read 2 more answers
In the diagram below, the radii of the two concentric circles are 3 centimeters and 7 centimeters, respectively.
True [87]

Answer:

125.6 cm²

Step-by-step explanation:

Area of the shaded region = area of larger circle - area of the smaller circle

Area of the smaller circle = πr²

π = 3.14, r = 3 cm

Area of smaller circle = 3.14*3² = 3.14*9 = 28.26 cm²

Area of larger circle = πr²

π = 3.14, r = 7

Area of larger circle = 3.14*7² = 3.14*49 = 153.86 cm²

Area of the shaded region = 153.86 - 28.26 = 125.6 cm²

5 0
3 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
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