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3 years ago

What is the correct answer

Mathematics

2 answers:

Ksju [112]3 years ago

4 0

The correct answer is C. If you reduce the fraction 36/18, it reduces to 2/1 or simply, 2. So, both fractions equal 2.

aksik [14]3 years ago

4 0

Answer: C

Step-by-step explanation:

Reduce the fraction 36/18 it is reduced to 2/1 so that means the answer would be 2

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Suppose that you began a one-year study of tuberculosis (TB) in a subsidized housing community in the Lower East Side of New Yor

Rufina [12.5K]

Answer:

The subsidized housing community in the lower East side of New York City is a dynamic population because people moved out of the population and others died while the survey was still being conducted.

The prevalence of TB on the screened community on January 1st is $\frac{30}{500} or = 0.06$

Step-by-step explanation:

Prevalence is given by; the number of persons affected by TB/ total number of people in the the study or survey.

3 0

3 years ago

Put in order from greatest to least<br>2.96 , 3 1/5, 3.48, 3 1/4 <br><br>

Tamiku [17]

2.96, 3 1/5, 3 1/4, 3.48

6 0

3 years ago

I really need help! come ASAP!!!

DiKsa [7]

100 minus 75 would be 25%
Turn 25% into a decimal and you would get .25
Then multiply that by 15 and you would get $3.75

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The basketball would cost $11.25.

Hope this helps!

7 0

3 years ago

Simplify -20y+30/ -2y+6

balu736 [363]

Answer:

− 3 5 + 6

Step-by-step explanation:

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4 0

3 years ago

I am confused in this can someone help?

fgiga [73]

Answer:

$\huge\boxed{\sf a = -12 , b = 8}$

Step-by-step explanation:

<u>Given polynomial is:</u>

$f(x) = ax^3+ b^2 + 3x + 4$

$\rule[225]{225}{2}$

First factor is (x-1)

Let x - 1 = 0 => x = 1

Putting this in the above polynomial

$f(1) = a(1)^3 + b(1)^2 + 3(1) + 4$

Given that it's remainder is 3

$3 = a + b + 3 + 4$

$3 = a + b + 7$

Subtracting 7 to both sides

$-4 = a + b\\OR \\$

$\rule[225]{225}{2}$

Second Factor is 2x + 1

Let 2x + 1 = 0 => x = - 1 / 2

Putting in the above polynomial

$f(-\frac{1}{2} ) = a (-\frac{1}{2} )^3 + b (-\frac{1}{2} )^2 + 3 (-\frac{1}{2} ) + 4$

The remainder is 6

$6 = -\frac{a}{8} + \frac{b}{4} - \frac{3}{2} + 4\\6 - 4 = -\frac{a}{8} + \frac{b}{4} - \frac{3}{2}\\2 = \frac{-a + 2b -12 }{8} \\-a + 2b - 12 = 16\\-a + 2b = 16 + 12\\$

$\rule[225]{225}{2}$

Adding both equations

a + b - a + 2b = -4 + 28

3b = 24

Dividing both sides by 3

b = 8

$\rule[225]{225}{2}$

Putting b = 8 in Equation (1)

a + 8 = -4

a = - 4 - 8

a = -12

$\rule[225]{225}{2}$

8 0

4 years ago