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Anika [276]
1 year ago
11

Which equations are true equations?

Mathematics
1 answer:
xz_007 [3.2K]1 year ago
3 0

Answer: 24 over 2 squared equals 50 minus 6 squared minus 8

56 divided by 8 plus 3 squared equals 2 times 2 cubed

Step-by-step explanation:

24/2^2 = 50-6^2 - 8

24/4 = 50-36-8

6 = 14-8

6=6

39-3*6 = 6*10/4 + 4

39 - 18 = 15 + 4

21 = 19

9^2 - 5 ^ 2 = 4 ^ 2 - 7

81 - 25 = 16 - 7

56 = 9

56/8 + 3^2 = 2 * 2^3

7 + 9 = 2 * 8

16 = 16

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5 minutes and 52 seconds rounded to the nearest minute
kirill [66]

Answer: 6 minutes

Step-by-step explanation: the 52 seconds rounds up to a full minute so it is 5.52 rounded up to 6 minutes

5 0
3 years ago
Read 2 more answers
72.4 divided by 4 please help!!!!
wariber [46]

Answer:

18.1

hope it helps mate

8 0
3 years ago
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Suppose f and g are continuous functions such that g(2) = 6 and lim x → 2 [3f(x) + f(x)g(x)] = 36. find f(2).
True [87]

Answer: f(2) = 4

Step-by-step explanation:

F(x) and g(x) are said to be continuous functions

Lim x=2 [3f(x) + f(x)g(x)] = 36

g(x) = 2

Limit x=2

[3f(2) + f(2)g(2)] = 36

[3f(2) + f(2) . 6] = 36

[3f(2) + 6f(2)] = 36

9f(2) = 36

Divide both sides by 9

f(2) = 36/9

f(2) = 4

7 0
3 years ago
If each of the following questions were asked to a group of second graders, which question would NOT be a statistical question?
sweet-ann [11.9K]

Answer:

d

Step-by-step explanation:

just makes sense bc they're all in 2nd grade

8 0
3 years ago
What is the first term of the geometric sequence whose fifth term is 1/24 and tenth term is 1/768
Neporo4naja [7]
An=a1r^(n-1)

given
a5=1/24
a10=1/768

we know that
a5=1/24=a1r^(5-1) and
a10=1/768=a1r^(10-1)

so
1/24=a1r^4
1/768=a1r^9

(a1r^9)/(a1r^4)=r^5=(1/768)/(1/24)=1/32

r^5=1/32
take 5th root of both sides
r=1/2

we have
a5=a1r^4=1/24
evaluate r^4 or (1/2)^4
1/16
a1(1/16)=1/24
times both sides by 16/1
a1=16/24
a1=2/3

the first term is 2/3



7 0
3 years ago
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