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skelet666 [1.2K]
3 years ago
11

Omar purchased a used vehicle for $6,500 one year ago. He drove 12,000 miles during the year and kept a record of all his expens

es. The variable costs totaled $1,972.50, and the fixed costs totaled $2,476.25. What was the cost per mile for Omar to operate his vehicle last year?
1 point
$0.16
$0.20
$0.37
$2.70
Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer:  $0.16

Step-by-step explanation:

Hi, to answer this question we simply have to divide the variable cost ($1,972.50) by the number of miles driven (the variable; 12,000 miles)

Mathematically speaking:

1,972.50 /12000 = 0.16

The cost per mile for Omar to operate his vehicle last year was $0.16

Feel free to ask for more if needed or if you did not understand something.

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Explain how you know that the equation 3x = 9 is equivalent to the equation x =3.
Marat540 [252]

Hey there!

If x = 3 then substitute it into the equation

3(3) = 9

3(3) = 9

9 = 9

Answer: 9 = 9, so this makes this statement is true

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

6 0
3 years ago
Consider 2 3/4 divided by 1/8.
PtichkaEL [24]
Fin the quotient . Show
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3 years ago
Jesse is sanding a circular wooden table that has a diameter of 6 ft. She can sand 5 square feet every hour. At this rate, appro
Ilya [14]

The time it will take Jesse to finish sanding the table is approximately 22.61 hours.

<h3>How to find the area of a circle?</h3>

Suppose the circle has radius of 'r' units, then, its area is given as:

A  = \pi \times (r)^2 sq. units

Since radius of a circle is half of its diameter, so if diameter is of 'd' length, then r= d/2, thus, area can be rewritten as:

A = \pi \times (\dfrac{d}{2})^2 sq. units

For the given case, sanding being done needs to be equal to the area of the circular table, as it has to be done for whole table's surface, which is circular, and area of sanding done will be equal to the area of that circular table.

The area of table(diameter given as 6 ft) is: A = \pi \times (\dfrac{d}{2})^2 \approx 3.14 \times 6^2 = 113.04 \: \rm ft^2

Since Jesse does 5 sq. feet per hour, let she takes T hours time to finish sanding the table, then we have:

\rm T \times 5\:  ft^2 = A \approx 113.04 \: ft^2\\\\\text{Dividing all sides by 5, we get}\\\\T = \dfrac{113.04}{5} \approx 22.61 \: hours

(since 5 sq. feet in 1 hours, then in T hours, T times 5 sq. feet will be done which is equal to area of table, as in approx T hours, she finishes sanding the table)

Thus, it will take approx 22.61 hours for Jesse to finish sanding the table.

Learn more about area of circle here:

brainly.com/question/13056790

8 0
2 years ago
Read 2 more answers
This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
3 years ago
Mario buys 2 pounds of hamburger and 1 pound of sausage. Sausage costs 10 cents more per pound than hamburger. If the total cost
Tasya [4]
Hamburger 1.80lbs sausage is 1.90lbs
1.80+ 1.80+ 1.90=$5.50
7 0
3 years ago
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