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musickatia [10]
2 years ago
10

1.The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD? 2.The equation of line A

B is y = 2x + 4. Write an equation of a line parallel to line AB in slope-intercept form that contains point (3, −2). 3.The equation of line QR is y = negative 1/2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6). 4.Line WX contains (−1, 2) and (4, 12) Line YZ contains points (5, 8) and (−2, −6). Lines WX and YZ are 5.Line CD contains points A (4, −7) and B (4, 8). The slope of line CD
Mathematics
2 answers:
Helga [31]2 years ago
8 0

Answer:

m= y2-y1 ÷ X2 - X1

Step-by-step explanation:

gogolik [260]2 years ago
5 0
So here's how to do it,
slope intercept form is y=mx+b
m is the slope, b is the y- intercept, X is your unknown variable.

you need to solve to get y by its self to get your slope.

for perpendicular lines flip the slope

ex 1, smy=2x+6 --- slope of a perpendicular line will be 1/2

ex 2, y=3/2+8 ---8 perpendicular lien would have a slope of 2/3

parallel lines have the same slope so any equation with with the same slope will be parallel if it has the same degree.

ex. y=2x+14 is parallel to y= 2x+56

slope can be found using the following formula if you have two sets of points on the same line

m= y2-y1 ÷ X2 - X1
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Sunny_sXe [5.5K]

Answer:

In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

Step-by-step explanation:

Given equation is -14(3a+6)=12(6-4a)+12

To simplify the given equation:

-14(3a+6)=12(6-4a)+12

Taking all terms to one side

-14(3a+6)-12(6-4a)-12=0

-[14(3a+6)+12(6-4a)+12]=0

Now dividing by negative sign on the above equation we get

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