The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.
<h3>How to calculate the domain of the function?</h3>
In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:
0= -4.87t² + 18.75t.
4.87t(-t + 3.85) = 0
t = 0 or t = 3.85.
Therefore, the domain is 0 ≤ t ≤ 3.85 or (0, 3.85).
<h3>How to calculate the range of the function?</h3>
h(t) = -4.87t² + 18.75t
h(t) = -4.87(t² - 3.85t + 3.85 - 3.85)
h(t) = -4.87(t - 1.925)² + 18.05
Therefore, the range is 0 ≤ h ≤ 18.05 or (0, 18.75).
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Answer:
B.intrest fees
Step-by-step explanation:
Answer:
(2a, b )
Step-by-step explanation:
Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[ 
(x₁ + x₂ ), (y₁ + y₂ ) ]
Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus
midpoint = [ (2a + 2a), (2b + 0 ) ] = (2a, b )
Answer:
Step-by-step explanation:
Let 
, a reflection over the x-axis consists in the following operation:
If we know that 
and 
, then the points translated over the x-axis are 
and 
, respectively. The most precise description of the shape is a rectangle for the following facts:
1) 
and 
.
2) 
and 
have the same x-component.
3) 
and 
have the same x-component.
4) and have the same y-component.
5) and have the same y-component.
A representation of the shape is included below as attachment.
20 is the answer to the question you asked.
