1. Simplified already
2. 5x^2 x (3x+5)
3. 3x^3 x (3x^4 +11)
Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
Answer:
(x + 2) (x + 4)
Step-by-step explanation:
Before looking at my explanation make sure next time you are going to ask another question write the numbers that include exponents like this: x^2 instead of x2
Factor out x^2:
x + x
Factor out 6x:
Since it is in the bx form we’ll need two numbers be add so it can be equivalent to 6x
Answer: 4 and 2
Factor out 8:
4 x 2
Now start with the 8 and 6x
(? + 4) + (? + 2)
Then finish it off with x
(x + 4) (x + 2)
Answer:
Sarah's Store
Step-by-step explanation: