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Lorico [155]
3 years ago
11

Which system of linear inequalities is represented by the graph?

Mathematics
2 answers:
fenix001 [56]3 years ago
7 0
<h2>Answer:</h2>

The system of linear inequalities which is represented by the  graph is:

        y>x-2 and    y<x+1

<h2>Step-by-step explanation:</h2>

The first inequality--

It is a dotted line which passes through (-1,0) and (0,1) and the shaded region is below the line.

first we find the equation of line:

The equation of a line passing through (a,b) and (c,d) is given by:

y-b=\dfrac{d-b}{c-a}\times (x-a)

Hence,

(a,b)=(-1,0) and (c,d)=(0,1)

Hence, the equation of line is:

y-0=\dfrac{1-0}{0-(-1)}\times (x-(-1))\\\\i.e.\\\\y=\dfrac{1}{1}\times (x+1)\\\\i.e.\\\\y=x+1

Also, the inequality is strict since the line is dotted.

Hence, the inequality is given by: y<x+1

The second inequality --

is a dotted line which passes through (0,-2) and (2,0)

and the shaded region is above the line.

The equation of line is given by:

  y=x-2

and the inequality is strict.

Hence, the inequality is given by:

        y>x-2

ELEN [110]3 years ago
6 0
I can’t see it clearly but so far the answer is D. Hope this helps!
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Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
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<h3>let's solve:</h3>
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  1. \sf substitute \: the \: value \: of \: y :  \\  \sf  - x + 2 = 3x - 4
  2. \sf add \: x \: to \: both \: sides :  \\  \sf  - x + x + 2 = 3x + x - 4 \\  \sf 4x - 4 = 2
  3. \sf add \: 4 \: to \: both \: sides :  \\  \sf xx - 4 + 4 = 2 + 4 \\ 4x = 6
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