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Lorico [155]
3 years ago
11

Which system of linear inequalities is represented by the graph?

Mathematics
2 answers:
fenix001 [56]3 years ago
7 0
<h2>Answer:</h2>

The system of linear inequalities which is represented by the  graph is:

        y>x-2 and    y<x+1

<h2>Step-by-step explanation:</h2>

The first inequality--

It is a dotted line which passes through (-1,0) and (0,1) and the shaded region is below the line.

first we find the equation of line:

The equation of a line passing through (a,b) and (c,d) is given by:

y-b=\dfrac{d-b}{c-a}\times (x-a)

Hence,

(a,b)=(-1,0) and (c,d)=(0,1)

Hence, the equation of line is:

y-0=\dfrac{1-0}{0-(-1)}\times (x-(-1))\\\\i.e.\\\\y=\dfrac{1}{1}\times (x+1)\\\\i.e.\\\\y=x+1

Also, the inequality is strict since the line is dotted.

Hence, the inequality is given by: y<x+1

The second inequality --

is a dotted line which passes through (0,-2) and (2,0)

and the shaded region is above the line.

The equation of line is given by:

  y=x-2

and the inequality is strict.

Hence, the inequality is given by:

        y>x-2

ELEN [110]3 years ago
6 0
I can’t see it clearly but so far the answer is D. Hope this helps!
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Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

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Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

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