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3 years ago

What is the equation of the line?

Mathematics

1 answer:

prohojiy [21]3 years ago

7 0

Answer:

A) y = -1/2x + 1/2

Step-by-step explanation:

Find the y-intercept(when x = 0), which is 1/2.

Find the slope: m = y2-y1 / x2-x1

I used points: (3, -1), (-3,2)

m = 2 - (-1) / -3 - 3

m = 3 / - 6

m = -1/2

plug this into the slope intercept form equation: y = mx + b

y = -1/2x + 1/2

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5.5 divided by 83 in quotient

sammy [17]

the answer is 15.090090

7 0

3 years ago

1/3(4y-2)+ 1/9(6y+10)

alukav5142 [94]

The answers is 2y+4/9

Hope that helps!! :)

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3 years ago

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The volume of a cube is 8000 cubic feet, what is the area of one of its faces?

eimsori [14]

Since a cube is l x w x h, find the length of one side first:

∛8,000 = 20

The length of one side is 20 feet. This can represented as "s".

To find the area of one of the faces, use s²:

20² or 20 x 20 = 400

The area of one face is 400 ft²!

4 0

3 years ago

9(5x + 1) ÷ 3y

alexdok [17]

The expression obtained after solving the given expression is, $\rm \frac{(15x+3)}{y}$

<h3>What is a BODMAS rule?</h3>

For the Bracket, Order, Division, Multiplication, Addition, and Subtraction rules, BODMAS stands for Bracket, Order, Division, Multiplication, Addition, and Subtraction.

Given expression ;

9(5x + 1) ÷ 3y

Follow the BODMAS rule;

Step 1; Divide

$\rm \frac{9(5x+1)}{3y} \\\\ \frac{3(5x+1)}{y} \\\\$

Step 2; Multiply

$\rm \frac{9(5x+1)}{3y} \\\\ \frac{(15x+3)}{y} \\\\$

Hence the expression obtained after solving the given expression is, $\rm \frac{(15x+3)}{y}$

To learn more about the BODMAS rule, refer to brainly.com/question/23827397.

#SPJ1

4 0

2 years ago

Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.

NISA [10]

Answer:

$\frac{\sqrt{\pi}}{4}$

Step-by-step explanation:

You are going to integrate the following function:

$g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}$ (1)

furthermore, you know that:

$\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}$

lets call to this integral, the integral Io.

for a general form of I you have In:

$I_n=\int_0^{\infty}x^ne^{-ax^2}dx$

furthermore you use the fact that:

$I_n=-\frac{\partial I_{n-2}}{\partial a}$

by using this last expression in an iterative way you obtain the following:

$\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}}$ (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

$\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}$

5 0

3 years ago

Read 2 more answers