What is the sum of the measures of the exterior angles of a 53-gon
1 answer:
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The correct answer is the flagpole is <span>33 feet high</span>.
Explanation:
Please refer to the attached picture.
We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°
Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD
Solving for BC:
BC = CD · <span>tan α
= 40 </span>· tan (35)
= 28 feet
In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33
Hence, the flagpole is 33 feet high.
Explanation:
Please refer to the attached picture.
We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°
Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD
Solving for BC:
BC = CD · <span>tan α
= 40 </span>· tan (35)
= 28 feet
In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33
Hence, the flagpole is 33 feet high.
Given:
Number of students = 35
Two out of every five boys in the club are boys.
To find:
The number of students in the club that are boys.
Solution:
Two out of every five boys in the club are boys. It means, the ratio of boys to the total number of student is 2:5.
Let the number of boys be 2x and number of students be 5x.
According to the question,
Now, the number of boys is
Therefore, 14 students in the club are boys.