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cricket20 [7]
2 years ago
6

Kkkmnkf;d;klsnfksdjlkfjk;asjdk;fjkasjd;f. fdjnsa;fdadf

Mathematics
1 answer:
Pavel [41]2 years ago
4 0
Sjdlslsooccjjsjshhcndbsyyqtaoxppcjshwtzjcjcoslahbfidowhsbcc
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What is 5800 divided by 28
Taya2010 [7]
The answer is 207.14
6 0
3 years ago
Read 2 more answers
What is the distance between the point (10,12) and (-4,-36)
dimulka [17.4K]
Well using distance formula

d \:  =  \sqrt{(x {}^{2} }  - x {}^{1} ) + (y {}^{2}  + y {}^{1} )
The answer I got was Distance = 45.9 what ever unit of measure it might ask for. Feel free to check my math just in case.
4 0
3 years ago
3x-2y=6<br><br> y=3/2x-3<br><br> Find the slope, x-intercept, and y-intercept for both equations.
lys-0071 [83]

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have 3x - 2y = 6       <em>subtract 3x from both sides</em>

-2y = -3x + 6      <em>divide both sides by -2</em>

y = 3/2 x - 3

slope: m = 3/2

y-intercept: b = -3

x-intercept for y = 0. Substitute:

3/2 x - 3 = 0      <em>add 3 to both sides</em>

3/2 x = 3       <em>multiply both sides by 2/3</em>

x = 2

<h3>Answer:</h3><h3>slope = 3/2</h3><h3>y-intercept = -3</h3><h3>x-intercept = 2</h3>

----------------------------------------------------------------

y = 3/2 x - 3 it's the same function like first function.

8 0
3 years ago
The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand
NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in  foreign language=0.20

The probability than an American CEO can not transact business in foreign language=1-0.20=0.80

Total number of American CEOs  chosen=12

a. The probability that none can transact business in a foreign language=12C_0(0.20)^0(0.80)^{12}

Using binomial theorem nC_r(1-p)^{n-r}p^r

The probability that none can transact business in a foreign language=\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}

b.The probability that at least two can transact business in a foreign language=1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))

c.The probability that all 12 can transact business in a foreign language=12C_{12}(0.8)^0(0.2)^{12}

The probability that all 12 can transact business in a foreign language=\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}

5 0
3 years ago
{(-1, -1) (3.8) (2, 4)(2, 3), (7. -7) }
vodka [1.7K]

jStep-by-step explanation:

I cannot see the question

4 0
2 years ago
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