Multiples : these are what we get after multiplying a number by an integer (not a decimal or fraction)
Example : 6 * 1 = 6......6 * 2 = 12.....6 * 3 = 18......so 6,12, and 18 are multiples of 6.
factors : these are what we multiply by to get a number
Example : 1 * 6 = 6.....so 1 and 6 are factors of 6....2 * 3 = 6 ...so 2 and 3 are also factors of 6
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problem 1 : Look at ur clues...each number is less then or equal to 12....this right here eliminates D because of the 15. The greatest common factor of the 2 numbers is 2....and this eliminates B because if it has a factor of 2, it has to be an even number. So that leaves us with :
A. 6 and 10
C. 10 and 12
last clue....they have a least common multiple of 60...this means that ur 2 numbers cant have any other common multiples until 60.
6 * 10......both are multiples of 60...however, they are also both multiples of 30...so 60 is not the least common multiple of 6 and 10, it is 30.
Therefore, ur answer is C. 10 and 12....with the LCM of 60, LCF of 2 and < or = to 12
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problem 2 : GCF (greatest common factor) of 42 and 84
factors of 42 : 1,2,3,6,7,14,21,42
factors of 84 : 1,2,3,4,6,7,12,14,21,28,42,84
therefore, the GCF of these 2 numbers is 42
Answer:
84.3211111111/ 84.32/ 84.3
Step-by-step explanation:
In order to find range, you have to add all the numbers up and then divide by the amount of numbers that you have. So, you'd do 90.89+ 87+ 79+ 89+ 84+ 80+ 85+ 85+ 79= 758.89. Then, since you have nine numbers, you'd divide 758.89 by nine, which equals 84.3211111111, and is rounded to 84.32, or 84.3.
Answer:
12r-32
Step-by-step explanation:
Distribute the 4 between the different numbers.
3r * 4 = 12r and 8 * 4 = 32
So...you end up with 12r-32
if you've read those links already, you'd know what we're doing here.
we'll move the repeating part to the left-side of the dot, by multiplying by "1" and as many zeros as needed, or 10 at some power pretty much.
on 0.13 we need 100 to get 13.13.... and on 0.1234, we need 10000 to get 1234.1234....
![\bf 0.\overline{13}~\hspace{10em}x=0.\overline{13} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|lll|ll} \cline{1-3} &&\\ 100\cdot 0.\overline{13}& = & 13.\overline{13}\\ 100\cdot x&& 13 + 0.\overline{13}\\ 100x&&13+x \\&&\\ \cline{1-3} \end{array}\implies \begin{array}{llll} 100x=13+x\implies 99x=13 \\\\ x=\cfrac{13}{99} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 0.\overline{1234}~\hspace{10em}x=0.\overline{1234} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%20%5Cbf%200.%5Coverline%7B13%7D~%5Chspace%7B10em%7Dx%3D0.%5Coverline%7B13%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7B%7Clll%7Cll%7D%0A%5Ccline%7B1-3%7D%0A%26%26%5C%5C%0A100%5Ccdot%200.%5Coverline%7B13%7D%26%20%3D%20%26%2013.%5Coverline%7B13%7D%5C%5C%0A100%5Ccdot%20x%26%26%2013%20%2B%200.%5Coverline%7B13%7D%5C%5C%0A100x%26%2613%2Bx%0A%5C%5C%26%26%5C%5C%0A%5Ccline%7B1-3%7D%0A%5Cend%7Barray%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%0A100x%3D13%2Bx%5Cimplies%2099x%3D13%0A%5C%5C%5C%5C%0Ax%3D%5Ccfrac%7B13%7D%7B99%7D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A0.%5Coverline%7B1234%7D~%5Chspace%7B10em%7Dx%3D0.%5Coverline%7B1234%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%20)
