All categories

3 years ago

Will bought 3 college textbooks. One cost 32$, one cost 45$, and one cost 39$. What is the average price of his book?

Mathematics

1 answer:

Damm [24]3 years ago

5 0

Answer:

The average of all textbooks is $38.60.

Step-by-step explanation:

Here's why to calculate average we do sum of all numbers divided by the number of numbers, for example if we average 2 and 3, we do 2+3 divided by 2. Which happens to be 2.5. Now for this problem we divide the sum by 3.

Therefore getting our answer of $38.60.

If this helps hit the thank button!

You might be interested in

If <br> DF<br> and <br> GI<br> are parallel lines and mIHE = 65°, what is mDEH?

12345 [234]

Answer:

literally i have no clue sorry

Step-by-step explanation:

3 0

2 years ago

3y^2 + 3(4y^2 - 2) please help

Butoxors [25]

The roots of the quadratic equation 3y² + 3(4y² - 2) is ± √(1/7).

<h3>What is a quadratic equaton?</h3>

A quadratic equation is an algebraic expression in the form of variables and constants.

A quadratic equation has two roots as its degree is two.

Given, 3y² + 3(4y² - 2).

3y² + 12y² - 2.

14y² - 2.

Let 14y² - 2 = 0.

14y² = 2.

y² = (2/14).

y = ± √(2/14) Or ± √(2/2×7) Or ± √(1/7).

learn more about quadratic equations here :

brainly.com/question/17177510

#SPJ1

8 0

10 months ago

Function A is represented by the equation

Dafna1 [17]

Answer:

They have the same rate of change.

Step-by-step explanation:

Well the graph of Function B is y = 1 / 3x + 2

So they have the same rate of change, since they have the same slope.

5 0

3 years ago

A trucking firm suspects that the mean life of a certain tire. it uses is less than 33,000 miles. To check the claim, the firm r

Mice21 [21]

Answer:

We accept the alternate hypothesis. We conclude that the mean lifetime of tires is is less than 33,000 miles.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 33,000 miles

Sample mean, $\bar{x}$ = 32, 450 miles

Sample size, n = 18

Alpha, α = 0.05

Sample standard deviation, s = 1200 miles

a) First, we design the null and the alternate hypothesis

$H_{0}: \mu = 33000\text{ miles}\\H_A: \mu < 33000\text{ miles}$

b) Level of significance:

$\alpha = 0.05$

c) We use One-tailed t test to perform this hypothesis.

d) Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{32450 - 33000}{\frac{1200}{\sqrt{18}} } = -1.9445$

Now, $t_{critical} \text{ at 0.05 level of significance, 17 degree of freedom } = -1.7396$

Rejection area:

$t < -1.7396$

Since,

$t_{stat} < t_{critical}$

e) We fail to accept the null hypothesis and reject it as the calculated value of t lies in the rejection area.

f) We accept the alternate hypothesis. We conclude that the mean lifetime of tires is is less than 33,000 miles.

3 0

2 years ago

Divide both sides of 15=5x by 5 what is the result

svetlana [45]

90% of people marry their 7th grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say i love you

8 0

2 years ago

Read 2 more answers