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3 years ago

If the difference of two numbers is 43 and the sum of the numbers is 13, what are the numbers?

Mathematics

1 answer:

meriva3 years ago

4 0

Answer:

Numbers are 28 and -15

Step-by-step explanation:

Mark first number X, and second number Y, then:

x-y=43

and

x+y=13

We get system of two equations. Solve it by add both them together:

x-y+x+y=43+13

2x=56

x=28 we get first number

x+y=13

28+y=13

y=13-28

y=-15

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The answer to your question is y=-5

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2 years ago

The formula f(x + 1) = Two-thirds(f(x)) defines a geometric sequence where f(1) = 18. Which explicit formula can be used to mode

astraxan [27]

Answer:

The explicit formula is Tn = 18[(2/3)^(n-1)]

Where n is the term we are looking for

Step-by-step explanation:

Here, we want to get an explicit formula to model the equation

Now, F(2) = 2/3 * f1 = 2/3 * 18 = 12

F(3) = 2/3 * f(2) = 2/3 * 12 = 8

F(4) = 2/3 * F(3) = 2/3 * 8 = 16/3

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3 years ago

8th term of 24,20,50/3

Tomtit [17]

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Step-by-step explanation:

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2 years ago

On a piece of paper, graph y < 3/4 x+2 Then determine which answer matches the graph drew.

OleMash [197]

Step-by-step explanation:

Given inequality is $y$ .

To graph that inequality, first we need to graph the line $y=\frac{3}{4}x+2$ . Then shade it for the inequality symbol <.

Graphing line can be done using two points.

plug x=0 into $y=\frac{3}{4}x+2$ , we get:

$y=\frac{3}{4}*0+2=2$

Hence first point is (0,2)

Similarly plug any random number for x say x=4, we get:

$y=\frac{3}{4}*4+2=5$

Hence first point is (4,5).

Now we just need to graph both points and join them by a dotted line. because we have < not <=.

Next part is to test for shading.

Which can be done using any test point which is not on the given line. Say (0,0)

plug x=0,y=0 into $y$ .

$0$

0<2

which is true, hence shading will be in direction of test point (0,0).

Hence final answer will be the choice which looks like the graph attached below;

3 0

2 years ago

Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me

Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

$V= \pi r^2 h$

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

$dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr$

So finding the partial derivatives we get

$dV =\pi r^2 dh + \pi 2r h dr$

$dV =\pi r^2 dh + 2\pi r h dr$

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

$dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)$

That give us

$V= 28 \pi \, cm^3$

Or in decimal value

$\boxed{dV= 87.96 \, cm^3}$

Thus the volume of metal in the can is 87.96 cubic cm.

6 0

3 years ago