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2 years ago

10 : 18 = _______ : 9

Mathematics

1 answer:

Vera_Pavlovna [14]2 years ago

8 0

The answer is 5:9 because 18 in half is 9 therefore 10 in half is 5

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A student's course grade is based on one midterm that counts as 5% of his final grade, one class project that counts as 10% of h

LiRa [457]

Answer:

<u>The student's final score is 77.2 and he earned a C letter grade</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the math problem correctly:

Midterm = 5% of the final grade and score of 60

Class project = 10% of the final grade and score of 92

Set of homework = 35% of the final grade and score of 80

Final exam = 50% of the final grade and score of 74

2. What is the student's final score?

Final score = (60 * 0.05) + (92 * 0.1) + (80 * 0.35) + (74 * 0.5)

Final score = 3 + 9.2 + 28 + 37

Final score = 77.2 and letter grade of C

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2 years ago

PTC is a substance that has a strong bitter taste for some people and is tasteless for others. The ability to taste PTC is inher

lana66690 [7]

Answer:

a) $n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83$

And rounded up we have that n=4906

b) For this case since we don't have prior info we need to use as estimatro for the proportion $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724$

And rounded up we have that n=6724

Step-by-step explanation:

We need to remember that the confidence interval for the true proportion is given by :

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Part a

The estimated proportion for this case is $\hat p =0.76$

Our interval is at 90% of confidence, and the significance level is given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . The critical values for this case are:

$z_{\alpha/2}=-1.64, t_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

The margin of error desired is given $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Replacing we got:

$n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83$

And rounded up we have that n=4906

Part b

For this case since we don't have prior info we need to use as estimatro for the proportion $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724$

And rounded up we have that n=6724

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3 years ago

Which applies the power of a power rule properly to simplify this expression?

Blababa [14]

Answer:

its D the last one

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One number is 6 times a first number. a third number is 100 times than the first number. If the sum of the three numbers is 784

sesenic [268]

It would be any number times 0 so yeah I hope this helps

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2 years ago

In standard notation 208.06 is written as

andreyandreev [35.5K]

Answer:

2.0806 × 10²

Step-by-step explanation:

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